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3 years ago

Solve each equation. X – 10 = 4 Math

Mathematics

2 answers:

garik1379 [7]3 years ago

7 0

Answer:

x=14

Step-by-step explanation:

suter [353]3 years ago

6 0

Answer:

x=14

Step-by-step explanation:

You might be interested in

The table shows the solution to the equation |2x − 5| − 2 = 3: Step 1 |2x − 5| = 3 + 2 Step 2 |2x − 5| = 5 Step 3 2x − 5 = 5 or

telo118 [61]

|2x − 5| − 2 = 3
1) |2x − 5| = 3 +2
2) |2x − 5| = 5
3) 2x-5 = 5, or 2x-5= -5
4)2x=10, or 2x=0
5) x = 5 , or x = 0

Check:
 |2x − 5| − 2 = 3
|2*5− 5| − 2 = 3 or |2*0 − 5| − 2 = 3
|5|-2=3 or |-5| -2 =3
3=3 (true) or 3=3 (true)

All steps are correct.

3 0

3 years ago

Item 7

Mariulka [41]

Answer:

$A = 74.7^\circ$

$B = 42.5^\circ$

$C = 62.8^\circ$

Step-by-step explanation:

Given

$A = (-1,2) \to (x_1,y_1)$

$B = (2,8) \to (x_2,y_2)$

$C = (4,1) \to (x_3,y_3)$

Required

The measure of each angle

First, we calculate the length of the three sides of the triangle.

This is calculated using distance formula

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2$

For AB

$A = (-1,2) \to (x_1,y_1)$

$B = (2,8) \to (x_2,y_2)$

$d = \sqrt{(-1 - 2)^2 + (2 - 8)^2$

$d = \sqrt{(-3)^2 + (-6)^2$

$d = \sqrt{45$

So:

$AB = \sqrt{45$

For BC

$B = (2,8) \to (x_2,y_2)$

$C = (4,1) \to (x_3,y_3)$

$BC = \sqrt{(2 - 4)^2 + (8 - 1)^2$

$BC = \sqrt{(-2)^2 + (7)^2$

$BC = \sqrt{53$

For AC

$A = (-1,2) \to (x_1,y_1)$

$C = (4,1) \to (x_3,y_3)$

$AC = \sqrt{(-1 - 4)^2 + (2 - 1)^2$

$AC = \sqrt{(-5)^2 + (1)^2$

$AC = \sqrt{26$

So, we have:

$AB = \sqrt{45$

$BC = \sqrt{53$

$AC = \sqrt{26$

By representation

$AB \to c$

$BC \to a$

$AC \to b$

So, we have:

$a = \sqrt{53$

$b = \sqrt{26$

$c = \sqrt{45$

By cosine laws, the angles are calculated using:

$a^2 = b^2 + c^2 -2bc \cos A$

$b^2 = a^2 + c^2 -2ac \cos B$

$c^2 = a^2 + b^2 -2ab\ cos C$

$a^2 = b^2 + c^2 -2bc \cos A$

$(\sqrt{53})^2 = (\sqrt{26})^2 +(\sqrt{45})^2 - 2 * (\sqrt{26}) +(\sqrt{45}) * \cos A$

$53 = 26 +45 - 2 * 34.21 * \cos A$

$53 = 26 +45 - 68.42 * \cos A$

Collect like terms

$53 - 26 -45 = - 68.42 * \cos A$

$-18 = - 68.42 * \cos A$

Solve for $\cos A$

$\cos A =\frac{-18}{-68.42}$

$\cos A =0.2631$

Take arc cos of both sides

$A =\cos^{-1}(0.2631)$

$A = 74.7^\circ$

$b^2 = a^2 + c^2 -2ac \cos B$

$(\sqrt{26})^2 = (\sqrt{53})^2 +(\sqrt{45})^2 - 2 * (\sqrt{53}) +(\sqrt{45}) * \cos B$

$26 = 53 +45 -97.67 * \cos B$

Collect like terms

$26 - 53 -45= -97.67 * \cos B$

$-72= -97.67 * \cos B$

Solve for $\cos B$

$\cos B = \frac{-72}{-97.67}$

$\cos B = 0.7372$

Take arc cos of both sides

$B = \cos^{-1}(0.7372)$

$B = 42.5^\circ$

For the third angle, we use:

$A + B + C = 180$ --- angles in a triangle

Make C the subject

$C = 180 - A -B$

$C = 180 - 74.7 -42.5$

$C = 62.8^\circ$

8 0

3 years ago

Find the slop of the line

Goshia [24]

Answer:

5/4 is your slope.

Step-by-step explanation:

5-0= 5

4-0= 4

slope is chang in y over change in x. Your first point is (0,0) and you second is (4,5).

6 0

3 years ago

PLZ HELP ASAP ASAP ASAP I HAVE TO GET THIS ODNE ITS DUE IN 20 MINUTES

pishuonlain [190]

Answer: C. -25 is the least one, B. 25 is the first one, A. 1/25 is the second, and D. -1/25 is the third. So in a simpler way Least to Greatest is -25, -1/25, 1/25, 25. I hope this helped!

5 0

2 years ago

Read 2 more answers

Distance between (-6, -2) and (0,-1)

s344n2d4d5 [400]

Hey there! I'm happy to help!

To find the distance between two points, you square the difference of the x-values and square the difference of the y-values, add them, and then you square root it!

First, we'll add our two x-values.

-6-0= -6

We square it, which means to multiply it by itself.

-6(-6)=36 (If you multiply an even number of negative numbers, your answer is positive. Since we have two negative numbers, we get positive 36)

Now, we do the same with the y-values.

-2-(-1)=-1 (two negatives make it a plus, as in minus minus 1 is plus one.)

We square it.

-1(-1)=1

Now, we add these x and y value differences.

36+1=37

Now, we find the square root using a calculator.

√37≈6.08

Have a wonderful day!

5 0

3 years ago