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Tcecarenko [31]
3 years ago
14

Jeff bought 1.5 pounds of pork and 2.5 pounds each of beef and chicken. What was the total cost of the meat Jeff bought? Type of

Meat Cost per Pound Beef $5.99 Chicken $4.79 Pork $3.64 Drag the numbers to complete the statement about what you need to find. Numbers may be used once, more than once, or not at all. 3.5231.52.514 Find the total cost of pounds of beef, pounds of chicken, and pounds of pork.
Mathematics
1 answer:
AveGali [126]3 years ago
7 0

Answer:

$32.41

Step-by-step explanation:

Given that:

\begin{center}\begin{tabular}{ c c }Type of Meat & Cost per pound \\Beef & \$5.99 \\Chicken & \$4.79\\Pork & \$3.64\\\end{tabular}\end{center}

Amount of pork bought by Jeff = 1.5 pounds

Amount of beef bought by Jeff = 2.5 pounds

Amount of chicken bought by Jeff = 2.5 pounds

Cost of number of pounds of each type of meat bought by Jeff can be calculated by multiplying the number of pounds by the cost of each type per pound.

Cost of pork for 1.5 pounds = 1.5 \times 3.64 = $5.46

Cost of beef for 2.5 pounds = 2.5 \times 5.99 = $14.975

Cost of chicken for 2.5 pounds = 2.5 \times 4.79 = $11.975

Total cost = Cost of pork + Cost of beef + Cost of chicken = 5.46 + 14.975 + 11.975 = <em>$32.41</em>

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4 0
2 years ago
How much money is 3462759.95 +463596739.98 equal<br> `100 points
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Answer:

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3 years ago
For 0 ≤ ϴ &lt; 2π, how many solutions are there to tan(StartFraction theta Over 2 EndFraction) = sin(ϴ)? Note: Do not include va
Black_prince [1.1K]

Answer:

3 solutions:

\theta={0, \frac{\pi}{2}, \frac{3\pi}{2}}

Step-by-step explanation:

So, first of all, we need to figure the angles that cannot be included in our answers out. The only function in the equation that isn't defined for some angles is tan(\frac{\theta}{2}) so let's focus on that part of the equation first.

We know that:

tan(\frac{\theta}{2})=\frac{sin(\frac{\theta}{2})}{cos(\frac{\theta}{2})}

therefore:

cos(\frac{\theta}{2})\neq0

so we need to find the angles that will make the cos function equal to zero. So we get:

cos(\frac{\theta}{2})=0

\frac{\theta}{2}=cos^{-1}(0)

\frac{\theta}{2}=\frac{\pi}{2}+\pi n

or

\theta=\pi+2\pi n

we can now start plugging values in for n:

\theta=\pi+2\pi (0)=\pi

if we plugged any value greater than 0, we would end up with an angle that is greater than 2\pi so,  that's the only angle we cannot include in our answer set, so:

\theta\neq \pi

having said this, we can now start solving the equation:

tan(\frac{\theta}{2})=sin(\theta)

we can start solving this equation by using the half angle formula, such a formula tells us the following:

tan(\frac{\theta}{2})=\frac{1-cos(\theta)}{sin(\theta)}

so we can substitute it into our equation:

\frac{1-cos(\theta)}{sin(\theta)}=sin(\theta)

we can now multiply both sides of the equation by sin(\theta)

so we get:

1-cos(\theta)=sin^{2}(\theta)

we can use the pythagorean identity to rewrite sin^{2}(\theta) in terms of cos:

sin^{2}(\theta)=1-cos^{2}(\theta)

so we get:

1-cos(\theta)=1-cos^{2}(\theta)

we can subtract a 1 from both sides of the equation so we end up with:

-cos(\theta)=-cos^{2}(\theta)

and we can now add cos^{2}(\theta)

to both sides of the equation so we get:

cos^{2}(\theta)-cos(\theta)=0

and we can solve this equation by factoring. We can factor cos(\theta) to get:

cos(\theta)(cos(\theta)-1)=0

and we can use the zero product property to solve this, so we get two equations:

Equation 1:

cos(\theta)=0

\theta=cos^{-1}(0)

\theta={\frac{\pi}{2}, \frac{3\pi}{2}}

Equation 2:

cos(\theta)-1=0

we add a 1 to both sides of the equation so we get:

cos(\theta)=1

\theta=cos^{-1}(1)

\theta=0

so we end up with three answers to this equation:

\theta={0, \frac{\pi}{2}, \frac{3\pi}{2}}

7 0
3 years ago
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4 0
3 years ago
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