Intermediate Value Theorem: Suppose that f(x) is an arbitrary, continuous function on an interval [a,b] . If there exists a value L between f(a) and f(b) , then there exists a corresponding value c∈(a,b) , such that f(c)=L
f(x)=x3+4x−1
f(0)=−1f(1)=4
Since the function changes sign in the interval (0,1) , hence there exists a c∈(0,1) such that f(c)=0
Answer:
Choice C. -17
Step-by-step explanation:
6 to 7 = -13
7 to 8 = -15
8 to 9 = =17
(a) The parabola opens downward.
(b) The axis of symmetry is at x = -2.
(c) The vertex is at (-2,0).
(d) The x-intercepts is (-2,0), and the y-intercept is at (0,-1).
q=10
Remove the radical by raising each side to the index of the radical
Hope this helps!
Answer:
See Explanation
Step-by-step explanation:
8. (1)
Area of trapezoid = 1/2(sum of || sides) *perpendicular distance
36 =1/2(x+ y) * 6
36 = ((x + y)*3
36/3 = x + y
12 = x + y
x + y = 12.... (1)
8(2)
It is given that:
x = 2y....(2)
From equations (1) & (2)
2y + y = 12
3y = 12
y = 12/3
y = 4
From equation (2)
x = 2y = 2*4
x = 8
9.
Area of square = 1 square m
Side of square = 1 m
Area of circle = 1 square m
