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valina [46]
3 years ago
14

Use the Geometric Mean Theorem and your knowledge of proportions to find the value of x.

Mathematics
1 answer:
xenn [34]3 years ago
7 0

Answer:

x=9.6cm

Step-by-step explanation:

x=\frac{2Area}{20}\\\\Area = \frac{16 * 12}{2} = 96 cm^{2}\\   \\x = \frac{2 * 96}{20}  = \frac{192}{20}  = \frac{48}{5} = 9.6 cm

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The system of equation y=3/4 and y=-x+3 According to the graph, what is the solution to this system of equations?
djverab [1.8K]

Answer:

(2.25 , 0.75)

Step-by-step explanation:

solution is where the graphs intersect each other

3/4 = - x + 3

-x = 3/4 -3 = -2 1/4

x =2 1/4

4 0
2 years ago
Helppp which one is it pleasee
solong [7]

Answer:

I think is D because u are putting the opposite in the first solutions u got a positive equation so for the other solutions i think u maybe are going to got the opposite I may be wrong But I just trying to help so sorry if u got it wrong

4 0
3 years ago
You buy a calculator for $65. A 6% sales tax is added.
Vika [28.1K]
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4 0
2 years ago
corine in making potato salad for each bowl of potato salad she needs 1/4 cup of potatoes how many cups of potatoes will she use
NARA [144]

Answer:

8 cups of potatoes are needed

Step-by-step explanation:

One way of doing this work is to write out

1/4 cup                                             1 cup

------------- , which is equivalent to  ------------ (a unit rate)

 1 bowl                                              4 bowl

and then multiply this unit rate by 32 bowls:

(1/4)(32 bowls) = 8 cups of potatoes are needed

5 0
2 years ago
Let f(x)=x^3-x-1
alexira [117]
f(x) = x^3 - x - 1

To find the gradient of the tangent, we must first differentiate the function.

f'(x) = \frac{d}{dx}(x^3 - x - 1) = 3x^2 - 1

The gradient at x = 0 is given by evaluating f'(0).

f'(0) = 3(0)^2 - 1 = -1

The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.

The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so

y = -x + c

Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).

f(0) = (0)^3 - (0) - 1 = -1

So the point (0, -1) lies on the tangent. Substituting into the tangent equation:

y = -x + c \\\\ -1 = -(0) + c \\\\ -1 = c \\\\ \text{Equation of tangent is } \boxed{y = -x - 1}
6 0
3 years ago
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