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3 years ago

Use the Geometric Mean Theorem and your knowledge of proportions to find the value of x.

Mathematics

1 answer:

xenn [34]3 years ago

7 0

Answer:

$x=9.6cm$

Step-by-step explanation:

$x=\frac{2Area}{20}\\\\Area = \frac{16 * 12}{2} = 96 cm^{2}\\ \\x = \frac{2 * 96}{20} = \frac{192}{20} = \frac{48}{5} = 9.6 cm$

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Plzzz help me with this I’ll give brainliest

scoray [572]

Answer18:

The quadrilateral ABCD is not a parallelogram

Answer19:

The quadrilateral ABCD is a parallelogram

Step-by-step explanation:

For question 18:

Given that vertices of a quadrilateral are A(-4,-1), B(-4,6), C(2,6) and D(2,-4)

The slope of a line is given m= $\frac{Y2-Y1}{X2-X1}$

Now,

The slope of a line AB:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{6-(-1)}{(-4)-(-4)}$

m= $\frac{7}{0}$

The slope is 90 degree

The slope of a line BC:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{6-6}{(-4)-(-1)}$

m= $\frac{0}{(-3)}$

The slope is zero degree

The slope of a line CD:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{(-4)-6}{2-2}$

m= $\frac{-10}{0}$

The slope is 90 degree

The slope of a line DA:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{(-1)-(-4)}{(-4)-(2)}$

m= $\frac{3}{-6}$

m= $\frac{-1}{2}$

The slope of the only line AB and CD are the same.

Thus, The quadrilateral ABCD is not a parallelogram

For question 19:

Given that vertices of a quadrilateral are A(-2,3), B(3,2), C(2,-1) and D(-3,0)

The slope of a line is given m= $\frac{Y2-Y1}{X2-X1}$

Now,

The slope of a line AB:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{2-3}{3-(-2)}$

m= $\frac{-1}{5}$

The slope of a line BC:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{(-1)-2}{2-3}$

m= $\frac{-3}{-1}$

m=3

The slope of a line CD:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{0-(-1)}{(-3)-2}$

m= $\frac{-1}{5}$

The slope of a line DA:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{3-0}{(-2)-(-3)}$

m=3

The slope of the line AB and CD are the same

The slope of the line BC and DA are the same

Thus, The quadrilateral ABCD is a parallelogram

3 0

3 years ago

Find the equation of the axis of symmetry and the coordinates of the vertex of the graph of each function y= 4x^2 - 2

alisha [4.7K]

Answer:y

−

Step-by-step explanation:

7 0

3 years ago

Can someone help with this problem on literal equations to get variable A by itself? Will give lots of points

-BARSIC- [3]

Answer:

Step-by-step explanation:

Part A

xf = xo + vo* t + 1/2 a*t^2 Subtract xo

xf - xo = 0*t + 1/2 a*t^2 multiply by 2

2(xf - xo) = at^2 divide by t^2

2(xf - xo ) / t^2 = a

Part B

Givens

xo =0

vo = 0

a = 10 m/s^2

xf = 120 m

Solution

xf = xo + vo* t + 1/2 a*t^2 Substitute the givens

120 = 0 + 0 + 1/2 * 10 * t^2 Multiply by 2

120*2 = 10* t^2

240 = 10*t^2 Divide by 10

240/10 = t^2

24 = t^2 take the square root of both sides.

√24 = √t^2

t = √24

t = √(2 * 2 * 2 * 3)

t = 2√6

8 0

3 years ago

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Sergio [31]

The answer to this question is c=3

3 0

3 years ago

Mari used a thermometer to record temperatures of -3.4 Celsius and 1.6 Celsius . Which temperature in degrees is lower

madam [21]

I think is would be -3.4

3 0

3 years ago