I suppose you want to know such number. Since we have a two digit number consisting of two consecutive integers, the only possible numbers are:

Since we sorted all the cases out, we simply have to check which one satisfies the requirement. For each number, we'll write four times the the sum of its digits, and add 6, hoping to get the original number.



So, the answer is 34.
Answer:
The probability that seven or more of them used their phones for guidance on purchasing decisions is 0.7886.
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Step-by-step explanation:
<em>The question is incomplete:</em>
<em>What should I buy? A study conducted by a research group in a recent year reported that 57% of cell phone owners used their phones inside a store for guidance on purchasing decisions. A sample of 14 cell phone owners is studied. Round the answers to at least four decimal places. What is the probability that seven or more of them used their phones for guidance on purchasing decisions? </em>
We can model this as a binomial random variable, with p=0.57 and n=14.

a) We have to calculate the probability that seven or more of them used their phones for guidance on purchasing decisions:




Hello :
the general term is :
an = a1+(n-1)×d
or : an = ap +(n-p)×d......d is common diffrence
let : n=10 and p= 4
a10 = a4 +(10-4)×d
64 = 22 + 6d
6d = 42
d= 7
conclusion :
a4 = 22
a3 = 22-7=15
a2=15-7=8
a1= 8-7=1
<span>the first five terms : 1 , 8 , 15 , 22</span>
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