Here's what you have to keep saying to yourself until it carves a new
groove into your brain and you don't have to think about it any more:
<em> " log(x) = the power that 10 must be raised to </em>
<em> in order to wind up with 'x'. "</em>
You said 2.36 = -log(x)
Multiply each side by -1 : log(x) = -2.36
Now translate it into the mantra:
<em> The power that 10 must be raised to </em>
<em> in order to wind up with 'x' is -2.36 .</em>
Do you see what that means ? ! ?
If the power that 10 must be raised to in order to wind up with 'x'
is -2.36, then all you have to do to find 'x' is raise 10 to the power
of -2.36 ! You can do that with about 4 clicks on your calculator.
10^(-2.36) = <em>0.004365...</em> (rounded)
And if you don't quite believe it, it's even easier to check it.
Punch " 0.004365 " into your calculator, and then touch the
" 10^x " key, and something very close to -2.36 will pop up
right there, before your wondrous eyes.
Answer:
105ft per minute
Step-by-step explanation:
well, if he/she walks 7ft in 4s, then you divide 60/4. In which you get 15.
15•7=105
Answer:
a)
b)
c)
Step-by-step explanation:
The problem states that there is a 97% probability that a parts inspected is classified correctly. So, there is a 3% probability that a part inspected is not classified correctly.
So
(A) x = 0, f(x) = ?
What is the probability that each part is not classified correctly?
There is a 0.0027% probability that no part is classified correctly
(B) x = 1, f(x) = ?
What is the probability that exactly one part is classified correctly?
We have to take into account that it may be the first part classified correctly, the second or the third. So we have to permutate. We have a permutation of 3 parts with 1(classified correctly) and 2(classified incorrectly) repetitions.
So
There is a 0.2619% probability that no part is classified correctly.
(C) x = 2, f(x) = ?
What is the probability that exactly two parts are classified correctly?
We also have the permutation of 3 parts with 2 and 1 repetitions.
So:
There is a 8.4681% probability that exactly two parts are classified correctly.
(D) x = 3, f(x) = ?
There is a 91.2673% probability that every part is classified correctly