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Tatiana [17]
3 years ago
12

Interest paid on £2500 at an interest at an interest rate of 15%

Mathematics
1 answer:
postnew [5]3 years ago
8 0

Answer:

  • £375

Step-by-step explanation:

  • Amount = £2500
  • Interest rate = 15%

<u>Interest </u>

  • £2500*15/100 = £375
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53 articles? Because josh wrote 13 plus 20 that Paulette wrote then Jeff wrote as many as Paulette so another 20.
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What is the equation of the line, in point-slope form, that passes through the points (9, 1) and (4, 16)?
Marina86 [1]

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3 years ago
Find the average value of f(x)=e2x over the interval [2, 4].
shusha [124]
<h2>Option B is the correct answer.</h2>

Step-by-step explanation:

We need to find average value of e^{2x} in [2,4]

Area of e^{2x} in [2,4] is given by

                  \int_{2}^{4}e^{2x}dx=\frac{1}{2}\times \left [ e^{2x}\right ]^4_2\\\\\int_{2}^{4}e^{2x}dx=\frac{1}{2}\times(e^8-e^4)=1463.18

Area of e^{2x} in [2,4] = 1463.18

Difference = 4 - 2 = 2

Average value = Area of e^{2x} in [2,4] ÷ Difference

Average value = 1463.18 ÷ 2

Average value = 731.59

Option B is the correct answer.

5 0
3 years ago
What is the missing angle in this triangle?
Masteriza [31]

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5 0
3 years ago
If x= 1/2-√3 , prove that x³-2x²-7x+5=3
prohojiy [21]
x=\frac{1}{2}-\sqrt3\\\\x^3-2x^2-7x+5=3\\\\(\frac{1}{2}-\sqrt3)^3-2(\frac{1}{2}-\sqrt3)^2-7(\frac{1}{2}-\sqrt3)+5\\\\=(\frac{1}{2})^3-3\cdot(\frac{1}{2})^2\cdto\sqrt3+3\cdot\frac{1}{2}\cdot(\sqrt3)^2-(\sqrt3)^3-...\\\\...-2[(\frac{1}{2})^2-2\cdot\frac{1}{2}\cdot\sqrt3+(\sqrt3)^2]-\frac{7}{2}+7\sqrt3+5

=\frac{1}{8}-\frac{3\sqrt3}{4}+\frac{9}{2}-3\sqrt3-2(\frac{1}{4}-\sqrt3+3)-\frac{7}{2}+7\sqrt3+5\\\\=\frac{1}{8}+\frac{9}{2}-\frac{1}{2}-6-\frac{7}{2}+5-\frac{3}{4}\sqrt3-3\sqrt3+2\sqrt3+7\sqrt3\\\\=\frac{1}{8}+\frac{1}{2}-1+5\frac{1}{4}\sqrt3=\frac{1}{8}-\frac{1}{2}+5\frac{1}{4}\sqrt3=\frac{1}{8}-\frac{4}{8}+5\frac{1}{4}\sqrt3\\\\=-\frac{3}{8}+5\frac{1}{4}\sqrt3\neq3
6 0
2 years ago
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