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3 years ago

Write the product (x-7)^2 in standard form

Mathematics

2 answers:

Lina20 [59]3 years ago

5 0

Answer:

x^2-14x+49

formula:

a^2-2ab+b^2

(a-b)^2

substitute values and

Wham bam yes ma'm

ella [17]3 years ago

5 0

The answer is x^2-14x+49 for this problem

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Find the maxium valve C=6x+2y. Subject to the following constraints x≥0, x≤5, y≥0, 4x-y≥1

Vadim26 [7]

Answer:

The maximum value of C is 68

Step-by-step explanation:

we have the following constraints

$x\geq 0$ ----> constraint A

$x\leq 5$ ----> constraint B

$y\geq 0$ ----> constraint C

$4x-y\geq 1$ ----> constraint D

Find out the area of the feasible region, using a graphing tool

The vertices of the feasible region are

(0,0),(5,19),(5,0)

see the attached figure

To find out the maximum value of the objective function C, substitute the value of x and the value of y of each vertex in the objective function and then compare the results

$C=6x+2y$

For (0,0) -----> $C=6(0)+2(0)=0$

For (5,19) -----> $C=6(5)+2(19)=68$

For (5,0) -----> $C=6(5)+2(0)=30$

therefore

The maximum value of C is 68

8 0

2 years ago

In a triangle the base is 4 inches and the height is 6 inches. Find the area. Type a numerical answer in the space

MAVERICK [17]

Answer:

Step-by-step explanation:

area =1/2 base×height

=1/2 ×4×6

=12

8 0

3 years ago

Find the value of x

Karo-lina-s [1.5K]

Answer:

x = 68°

Step-by-step explanation:

∠ DCB = ∠ EDC = 27° ( alternate angles )

Thus ∠ ECB = 23° + 27° = 50°

The sum of the 3 angles in a triangle = 180°, thus

x = 180° - (62 + 50)° = 180° - 112° = 68°

7 0

2 years ago

Read 2 more answers

Prove that sinxtanx=1/cosx - cosx

maks197457 [2]

Answer:

See below

Step-by-step explanation:

We want to prove that

$\sin(x)\tan(x) = \dfrac{1}{\cos(x)} - \cos(x), \forall x \in\mathbb{R}$

Taking the RHS, note

$\dfrac{1}{\cos(x)} - \cos(x) = \dfrac{1}{\cos(x)} - \dfrac{\cos(x) \cos(x)}{\cos(x)} = \dfrac{1-\cos^2(x)}{\cos(x)}$

Remember that

$\sin^2(x) + \cos^2(x) =1 \implies 1- \cos^2(x) =\sin^2(x)$

Therefore,

$\dfrac{1-\cos^2(x)}{\cos(x)} = \dfrac{\sin^2(x)}{\cos(x)} = \dfrac{\sin(x)\sin(x)}{\cos(x)}$

Once

$\dfrac{\sin(x)}{\cos(x)} = \tan(x)$

Then,

$\dfrac{\sin(x)\sin(x)}{\cos(x)} = \sin(x)\tan(x)$

Hence, it is proved

5 0

2 years ago

there are 2 ones, 1 five,3tens, and 1 twenty. if there are 28 bills in her wallet, what would you predict is the approximate val

Kruka [31]

There would be 8 ones, 4 fives, 12 tens, and 4 twenties. That together would be about $228

4 0

3 years ago