Answer:
The work done in stretching the spring is 8 lb.ft
Step-by-step explanation:
Given;
Applied force, F = 192 lb
extension of the spring, x = 3 ft
Determine the spring constant from the applied force and extension;

When the spring is stretched 6 inches beyond its natural length, the work done is calculated as follows;
x = 6 inches = 0.5 ft

Therefore, the work done in stretching the spring is 8 lb.ft
The correct answer among all is D. I'm in K12 8th grade by the way so nice to meet you :)
Answer:
I believe this is the answer
V=5000(1•0.085)^x
Step-by-step explanation:
sorry if its incorrect i just wanted to help
Answer:
30
Step-by-step explanation:
Write 10% as a decimal then divide 3 by 0.1 (10% as a decimal)
hope this is good owo
Answer:
B
Step-by-step explanation:
negative 6 times negative 6 equals 36