Ok, so I used the equation Y2 (4) - Y1 (-10) over X2 (2) -X1 (-5).
4 - -10 is 14 since if a minus sign is before a negative number, it becomes positive.
Same goes for 2 - -5. It is 7 since the minus sign is before the negative number. Final answer is 14/7 which can be simpflied to 2/1 since 14 divided by 7 =2. So the distance is 14\7, or 2\1.
(x+12)(x-3) Try this answer hopefully it is correct.
98.66074, you just multiply the two values
Answer: Yes, she could be considered similar to herself at 6 months of age.
In mathematics, the concept of similarity is about proportion relationships. In this problem, we are discussing the relationships between age, height and diameter. We are not discussing the absolute value of the numbers themselves.
For example in Geometry, a very small triangle can be similar to a very large triangle if all the angles of the triangle are congruent. The size doesn't matter.
Answer:
x = 
y = 
Step-by-step explanation:
![2x-3y=5\\5x=4y=14\\\\\left[\begin{array}{cc}2&-3\\5&-4\\\end{array}\right] \left[\begin{array}{c}x\\y\\\end{array}\right] =\left[\begin{array}{c}5\\14\\\end{array}\right]](https://tex.z-dn.net/?f=2x-3y%3D5%5C%5C5x%3D4y%3D14%5C%5C%5C%5C%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-3%5C%5C5%26-4%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D5%5C%5C14%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Let A = ![\\\left[\begin{array}{cc}2&-3\\5&-4\\\end{array}\right]](https://tex.z-dn.net/?f=%5C%5C%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-3%5C%5C5%26-4%5C%5C%5Cend%7Barray%7D%5Cright%5D)
The inverse of A multiplied by A = the identity matrix ![\left[\begin{array}{cc}1&0\\0&1\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%260%5C%5C0%261%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Inverse of A =
![\left[\begin{array}{ccc}-4&3\\-5&2\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-4%263%5C%5C-5%262%5C%5C%5Cend%7Barray%7D%5Cright%5D)
detA = ad - bc = 
Inverse of A = ![\left[\begin{array}{cc}\frac{-4}{7} &\frac{3}{7} \\\frac{-5}{7} &\frac{2}{7}\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Cfrac%7B-4%7D%7B7%7D%20%26%5Cfrac%7B3%7D%7B7%7D%20%5C%5C%5Cfrac%7B-5%7D%7B7%7D%20%26%5Cfrac%7B2%7D%7B7%7D%5C%5C%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{cc}\frac{-4}{7} &\frac{3}{7} \\\frac{-5}{7} &\frac{2}{7}\\\end{array}\right] \left[\begin{array}{ccc}5\\14\\\end{array}\right] = \left[\begin{array}{ccc}\frac{22}{7} \\\frac{3}{7} \\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Cfrac%7B-4%7D%7B7%7D%20%26%5Cfrac%7B3%7D%7B7%7D%20%5C%5C%5Cfrac%7B-5%7D%7B7%7D%20%26%5Cfrac%7B2%7D%7B7%7D%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%5C%5C14%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cfrac%7B22%7D%7B7%7D%20%5C%5C%5Cfrac%7B3%7D%7B7%7D%20%5C%5C%5Cend%7Barray%7D%5Cright%5D)