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Vesnalui [34]
3 years ago
7

Find the unknown measures. Round lengths to the nearest hundredth and angle measures to the nearest degree.

Mathematics
1 answer:
MatroZZZ [7]3 years ago
5 0
The answer is AB= 4.62; mA= 22; mB=68
You could quickly find the answer by just using Pythagorean theorem to find AB.
4.3^2 +1.7^2 = AB^2
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The amount of paper that the copy shop used this month was a 25% increase of the amount of paper they used last month. What perc
likoan [24]

Answer:

You didn't include any image here, but numerically, the amount of paper consumed this month is 125% compared to last month.

If last month's consumption is represented by 4 equal shapes, then the current month's consumption will be 5 shapes.  

If last month's consumption is represented by 8 equal shapes, then the current month's consumption will be 10 shapes.  

this pattern keeps repeating.

3 0
3 years ago
What is the exact perimeter of kite ? Show your work.
Afina-wow [57]

Answer:

<u>The perimeter of the kite is 29 units.</u>

Step-by-step explanation:

1. Let's use the Pythagorean Theorem to find the perimeter of the kite:

With the information given, we have four right triangles with a new point A, intersecting UW and VX. Those triangles are:

Δ UVA

Δ VWA

Δ UXA

Δ XWA

As we can see in the figure, length of UV and VW is the same and the length of UX and WX is also the same.

2. Let's find the value of UV and VW

UV is the hypotenuse of Δ UVA and it sides are 3 and 4 units length. So, we can calculate the length of UV this way:

Length of UV ² = UA ² + VA ²

Replacing with the real values:

Length of UV ² = 3 ² + 4 ²

Length of UV ² = 9 + 16

Length of UV ² = 25

√Length of UV ² = √25

<u>Length of UV  = 5 units ⇒ Length of VW = 5 units</u>

3. Let's find the value of UX and WX

UX is the hypotenuse of Δ UXA and it sides are 3 and 9 units length. So, we can calculate the length of UX this way:

Length of UX ² = UA ² + XA ²

Replacing with the real values:

Length of UX ² = 3 ² + 9 ²

Length of UX ² = 9 + 81

Length of UV ² = 90

√Length of UV ² = √90

<u>Length of UV  = 9.5 units (rounding to the nearest tenth) ⇒ Length of WX= 9.5 units</u>

<u>4. </u>Let's calculate the perimeter of the kite:

Perimeter of the kite = UV + VW + WX + UX

Perimeter of the kite = 5 + 5 + 9.5 + 9.5

<u>Perimeter of the kite = 29 units</u>

7 0
3 years ago
What is the degree of the polynomial 2x3 - 3x2 + 4x + 5
tia_tia [17]
With polynomials the degree is the highest power x or whatever the variable is raised to. In this case, the degree is 3 since the highest power x is raised to is x^3
4 0
3 years ago
The height of a sunflower increases from 82cm to 1 metre in a week.find the percentage increase in height
KATRIN_1 [288]
Find difference i.e 100-82=18
if 82 is 100%, what about 18?
(18*100)/82= 21.951 ans
5 0
3 years ago
david ran on a straight track. every time he ran 480m, he took a break. After 2 breaks, he still had to run 120 m to complete th
kipiarov [429]

Answer:

The distance of the playground is 540m

Step-by-step explanation:

Here, we are interested in calculating the length of the playground given the information in the question.

Where to attack the question from is the segment that states that he took a break after 480m and also had 2 breaks. Thus, the distance traveled would be 480 * 2 = 960 m

Now, to find the length of the track, we add the distance covered plus the distance uncovered. Mathematically that would be 960m + 120m = 1,080m

In the last part of the question, we are told that the track is twice as long as the playground. This means that the length of the playground or the distance of the playground is 1080/2 = 540 m

4 0
3 years ago
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