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3 years ago

9

Trey has three pairs of Vans, two pairs of Nikes, and four pairs of Adidas shoes in his shoe bin. One morning, the electricity w

ent out and Trey pulls two shoes at random. Remember each pair of shoes counts as 2 shoes.
a) What is the probability that he pulls out two adidas shoes without replacement? Round your answer to the nearest tenth of a percent.

%

b) What is the probability that he pulls out a Vans, decides that's not what he wants, so he replaces it then pulls out two Nike shoes?

Round your answer to the nearest tenth of a percent.

%

1 answer:

larisa86 [58]3 years ago

4 0

Answer: A) 40%

B)30%

Step-by-step explanation:

A) becase 4/9 as a percentage is 0.444444% and I rounded it to 0.4% then turned it into 40% cause its outta 100

MARK AS BRAINLEIST

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Time $t_1$ , distance of $d_1$ , v = 40. So

$v = \frac{d}{t}$

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On the second day, the velocity is $v = 60$ .

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On the first day, he traveled 20 more miles, which means that for the second day, the distance is: $d_1 - 20$

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Now, from the two equations, a system of equations can be built. So

$40 = \frac{d_1}{t_1}$

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Find the total distance traveled in the two days:

We solve the system of equation for $d_1$ , which gets the distance on the first day. The distance on the second day is $d_2 = d_1 - 20$ , and the total distance is:

$T = d_1 + d_2 = d_1 + d_1 - 20 = 2d_1 - 20$

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$d_1 - 20 = 60\frac{d_1}{40} - 120$

$d_1 = \frac{3d_1}{2} - 100$

$d_1 - \frac{3d_1}{2} = -100$

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Thus, the total distance is:

$T = 2d_1 - 20 = 2(200) - 20 = 400 - 20 = 380$

The total distance traveled in two days was of 380 miles.

For the relation between velocity, distance and time, you can take a look here: brainly.com/question/14307500

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