3 years ago

Which situation is best modeled by the expression 1/2 x 1/6.

Mathematics

1 answer:

yanalaym [24]3 years ago

6 0

Answer:

I'm gonna go with b p.s: sorry if im wrong

Step-by-step explanation:

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What is the equation for the vertical asymptote of the function shown below? f(x)=3x^4-3/2x-5

levacccp [35]

$f(x)= \frac{3x^4}{2x-5}$

the va's are where x is undefined, or where the denomenator is zero
first simplify if applicable
cannot simplify

set denom to zero
2x-5=0
2x=5
x=2.5

the vertical assemtote is vertical so it is x=2.5 or 5/2

the VA is x=5/2

3 0

2 years ago

At what point does the curve have maximum curvature? y = 9 ln(x) (x, y) =

Andrews [41]

y = 9ln(x)
y' = 9x^-1 =9/x
y'' = -9x^-2 =-9/x^2

curvature k = |y''| / (1 + (y')^2)^(3/2)

= |-9/x^2| / (1 + (9/x)^2)^(3/2)
= (9/x^2) / (1 + 81/x^2)^(3/2)
= (9/x^2) / [(1/x^3) (x^2 + 81)^(3/2)]
= 9x(x^2 + 81)^(-3/2).

To maximize the curvature,

we find where k' = 0. 
k' = 9 * (x^2 + 81)^(-3/2) + 9x * -3x(x^2 + 81)^(-5/2)
...= 9(x^2 + 81)^(-5/2) [(x^2 + 81) - 3x^2]
...= 9(81 - 2x^2)/(x^2 + 81)^(5/2)

Setting k' = 0 yields x = ±9/√2.

Since k' < 0 for x < -9/√2 and k' > 0 for x > -9/√2 (and less than 9/√2),
we have a minimum at x = -9/√2.

Since k' > 0 for x < 9/√2 (and greater than 9/√2) and k' < 0 for x > 9/√2,
we have a maximum at x = 9/√2.

x=9/√2=6.36

y=9 ln(x)=9ln(6.36)=16.66

the answer is
(x,y)=(6.36,16.66)

7 0

3 years ago

Twenty-eight slices of pizza cost $12. Approximately how much would 70 slices cost?

Mademuasel [1]

Answer:

$30.

Step-by-step explanation:

70/28 = 2.5

12 x 2.5 = 30

5 0