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love history [14]
4 years ago
15

At a scrapbooking party, guests brought a certain number of photographs to use, based on

Mathematics
1 answer:
Natali5045456 [20]4 years ago
8 0

Answer:

A small page can fit 2 photographs, and a large on can fit 2 photographs.

Step-by-step explanation:

Let the number of photographs on the small page be represented by m and that of large one by n.

Since the number of photographs on a page remains constant, then;

4m + 7n = 22 ........... 1

8m + 7n = 30 .......... 2

Multiply equation 1 by 2, and 2 by 1 to have;

8m + 14n = 44 ....... 3

8m + 7n = 30 ......... 4

subtract equation 4 from 3,

7n = 14

n = 2

Substitute the value of n in equation 1

4m + 7(2) = 22

4m + 14 = 22

4m = 8

m = 2

m = 2, n = 2

Therefore, a small page can fit 2 photographs, and a large on can fit 2 photographs so that the number of photographs n a page is constant.

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3 years ago
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Can you please help me solve these systems?
sveta [45]
<span>1)
11x+5y=20
2x+5y=-25

multiply the second equation by - 1 and add the result with the first equation:

11x + 5y = 20
- 2x - 5y = 25
-------------------
9x = 45

=> x = 45 / 9

=> x = 5

Replace in </span><span>2x+5y=-25

=> 2(5) + 5y = - 25

5y = - 25 - 10

5y = - 35

y = - 35 / 5

y = - 7


2)

3x+7y=-21

3x-7y=63</span>

Add the two equations:

3x + 3x + 0 = - 21 + 63

6x = 42

=> x = 42 / 6

=> x = 7

Replace in <span>3x-7y=63

3(7) - 7y = 63

=> 7y = 21 - 63

=-> 7y = - 42

=> y = - 42 / 6

=> y = - 7</span>
5 0
4 years ago
If 1/2 - 1/3=x then x=
ratelena [41]

Answer:

x=1/6

Step-by-step explanation:

1/2-1/3=x

x=1×3-1×3/6 [ take l.c.m]

x=3-2/6

x=1/6 .

8 0
3 years ago
If x is an even integer and y is an odd integer than yn yis a rational number
shtirl [24]

Answer:Since the integers are closed under addition, . m C n C 1/ is an integer, and hence the last equation shows that x C y is even. Therefore, we Page 3 Appendix C. Answers for Exercises 539 have proven that if x and y are odd integers, then x C y is an even integer. P1 There exists an integer k m D 2k.

Step-by-step explanation:

6 0
4 years ago
Misaka solved the radical equation x – 3 = square root of 4x-7 but did not check her solutions. (x – 3)2 = square root of 4x-7^2
Minchanka [31]

Answer:

x=8 is a true solution of the radical equation

Step-by-step explanation:

we have

x-3=\sqrt{4x-7}

Solve for x

squared both sides

(x-3)^{2}=4x-7\\\\x^{2}-6x+9=4x-7\\\\ x^{2}-10x+16=0

Convert to factored form

x^{2}-10x+16=(x-2)(x-8)

The solutions are x=2 and x=8

<u><em>Verify the solutions</em></u>

For x=2

Substitute in the original equation

2-3=\sqrt{4(2)-7}

-1=1 ----> is not true

therefore

x=2 is not a true solution of the radical equation

For x=8

Substitute in the original equation

8-3=\sqrt{4(8)-7}

5=5 ----> is true

therefore

x=8 is a true solution of the radical equation

3 0
4 years ago
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