3x+9=6x
-9 -9
—————
3x=6x-9
-6x -6x
—————
3x-6x=-9
-3x=-9
x=3
hope it helped
For a right triangle with legs legnth a and b and hyptonuse c
a^2+b^2=c^2
9 feet from base, that's one leg
wire is hypotnuse, it's 1 more than height on tree
c=b+1
so
9^2+b^2=(b+1)^2
81+b^2=b^2+2b+1
minus b^2+1 from both sides
80=2b
divide both sides by 2
40=b
c=b+1
c=40+1
c=41
legnth of wire is 41ft
Answer:
d=20
Step-by-step explanation:
To find the distance between 2 points we use the distance formula
d = √(x2 - x1)²+(y2 - y1)²
The given points are (x1= -8, y1 = -6) and (x2 = 4, y2 = 10).
Substitute the given points into the distance formula.
d = √(4 + 8)²+(10 +6)²
d = √144+252
d= √400
d = 20
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