All categories

2 years ago

Are these triangles similar? (worth 25 points)

Mathematics

1 answer:

zloy xaker [14]2 years ago

5 0

Find angleK:

Angle k = 180-45-85 = 50

Both triangles have an angle equal to 85 and 45, which makes the 3rd angle in both triangles equal to 50

Because all three angles are the same the triangles are similar.

You might be interested in

The point P(8, 6) is on the terminal side of θ. Evaluate sin θ.

vladimir2022 [97]

Ok so let me help you with this. Here is the procedure:
<span>r² = x² + y² = 8² + 6² = 100
r = 10
x = r cosθ
y = r sinθ
sinθ = y/r = 6/10 = 3/5
</span>Hope this is what you are looking for

3 0

3 years ago

Read 2 more answers

Issac put $5 in a shoe box every day for the months of april, may, and june. He then spent 75% of the money on baseball cards. H

igor_vitrenko [27]

As of 2021:
April-$150
May-$155
June-$150
Total-$455
Spent 75%=455/100x75
=341.25
455-341.25=$113.75
Round off to 3sf: $114
Have a good day

3 0

2 years ago

7 is subtracted from 7 times a number

PolarNik [594]

Answer:

(7x) - 7

Hope this helps!

8 0

2 years ago

Read 2 more answers

What is 28/40 in simplest form?

Artemon [7]

7/10 is the answer.....

8 0

2 years ago

Read 2 more answers

Find Horizontal and Vertical asymptotes for y=(x^2 -9)/(4x^2 +1)

Gnom [1K]

Answer: Horizontal asymptote is $\dfrac{1}{4}$ and vertical asymptotes are $\pm \dfrac{1}{2i}$

Step-by-step explanation:

Since we have given that

$y=\dfrac{x^2-9}{4x^2+1}$

We need to find the horizontal and vertical asymptotes.

Since vertical asymptotes will occur where the denominator becomes zero.

So, here denominator is $4x^2+1$

Now,

$4x^2+1=0\\\\4x^2=-1\\\\x^2=\dfrac{-1}{4}\\\\x=\pm \dfrac{1}{2i}$

And the horizontal asympototes will occur when the coefficient of higher degree of numerator is divided by coefficient of higher degree of denominator.

$y=\dfrac{1}{4}$

Hence, horizontal asymptote is $\dfrac{1}{4}$ and vertical asymptotes are $\pm \dfrac{1}{2i}$

8 0

2 years ago