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Murrr4er [49]
3 years ago
15

A promoter buys advertising in units of $30,000 each. If he buys two units of broadcast TV, one unit of cable TV, and two units

of radio, how much does he spend in advertising?
Mathematics
1 answer:
andriy [413]3 years ago
4 0

Answer:

$150,000

Step-by-step explanation:

The first step is to calculate the total number of units

= 2 +1 +2

= 5

If he buys at the rate of $30,000 for one unit then the total money spent on advertising can be calculated as follows

= 30,000 × 5

= 150,000

Hence the promoter spends $150,000 on advertising

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<em>Comment on this solution</em>

When a problem statement tells you the ratio of one kind of item to another, it is often convenient to group the items in that ratio and deal with the groups. Sometimes, there will be a few missing or left over, for example "10 more than 3 times as many." In those cases, you can make an adjustment to the total and still deal with the groups. (Any equations you might write will effectively do this same thing.)

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Step-by-step explanation:

Both of them had $x

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