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statuscvo [17]
3 years ago
15

Does a june bug have jaws?

Biology
1 answer:
Vesnalui [34]3 years ago
7 0
Yes mostly all beetles have mandibles.
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Many polyploid plants, such as the bananas shown here, are grown commercially because they are often larger and healthier than n
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The genetic mulation

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Which organs shown in the transparency are part of the frog's nervous system?
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The nervous system in a frog controls the activities of the organs of the body. It also would regulate the internal environment in one's body. All the organs which are also the same parts of nervous system of a vertebrate are present in a frog. The brain,spinal chord,the sympathetic and para sympathetic nerves,cranial nerves,spinal nerves,cranial nuclei and ganglia.
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Three questions to answer you can do however much you want but PLEASE ANSWER. If you put a link I’m reporting you
uranmaximum [27]

Answer:

Explanation:

Not sure about the first question but

#2: hybrid

#3: alleles

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2 years ago
Which of the choices below is the salt level-monitoring part of the nephron?
WINSTONCH [101]

Answer:

c. macula densa

Explanation:

The cells of the macula densa are sensitive to the concentration of sodium chloride in the distal convoluted tubule. They are a part of the nephron.

5 0
3 years ago
Alkaptonuria is an infrequent autosomal recessive condition. It is first noticed in newborns when the urine in their diapers tur
Arisa [49]

Answer:

See the answer below

Explanation:

Let the disorder be represented by the allele a.

Since the disease is an autosomal recessive one, affected individuals will have the genotype aa and normal individuals will have the genotype Aa or AA.

Since the four adults are carriers, their genotypes would be Aa.

                    Aa     x     Aa

Progeny:    AA    2Aa    aa

Probability of being affected = 1/4

Probability of being a carrier = 1/2

Probability of not being affected = 3/4

(a) The chance that the child second child of Mary and Frank will have alkaptonuria = 1/2

(b) The chance that  the third child of Sara and James will be free of the condition = 3/4

(c)

(d) If someone has no family history of the disorder, their genotype would be AA.

                 AA     x     aa

                        4 Aa

<em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history </em>= 0

(e)

(f) <em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history</em> = 0

5 0
3 years ago
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