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Semmy [17]
3 years ago
13

Creating a password with two letters followed by two one-digit numbers. (Find the total number of outcomes that are possible)

Mathematics
1 answer:
timofeeve [1]3 years ago
3 0

Answer:

67,600 possible outcomes

Step-by-step explanation:

In total, it's a four digit password.

For the first digit, which is a letter, there are 26 possibilities. The same goes for the second digit, so first multiply 26 x 26 (because that's the number of possibilities for the first two digits alone).

! if the letters have to be different then it would be 26 x 25 because there's one less letter for the second digit.

Next, 2 one digit numbers. There are 10 individual digits: 0,1,2,3,4,5,6,7,8,9, so after 26 x 26 x 10 x 10 for the total number of possibilities. If the numbers have to be different (and the letters too) then it'd be 26 x 25 x 10 x 9

so 26 x 26 x 10 x 10 = 67,600

hope this helps!

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Answer:

Los radios de los círculos son r_{1} \approx 9.995, r_{2} \approx 2.013, r_{3} \approx 7.592, respectivamente.

Las áreas de los círculos son A_{1} \approx 313.845, A_{2} \approx 12.730, A_{3} \approx 181.077, respectivamente.

Step-by-step explanation:

La circunferencia (s) se calcula mediante la siguiente fórmula:

s = 2\pi\cdot r (1)

Donde r es el radio del círculo.

Una vez hallado el radio, se determina el área de la figura geométrica (A) mediante la siguiente fórmula:

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Si conocemos que las circunferencias son s_{1} = 62.8, s_{2} = 12.65 y s_{3} = 47.7, respectivamente:

1) Radios de los círculos

r_{1} = \frac{s_{1}}{2\pi}, r_{2} = \frac{s_{2}}{2\pi}, r_{3} = \frac{s_{3}}{2\pi}

r_{1} \approx 9.995, r_{2} \approx 2.013, r_{3} \approx 7.592

2) Áreas de los círculos

A_{1} = \pi\cdot r_{1}^{2}, A_{2} = \pi\cdot r_{2}^{2}, A_{3} = \pi\cdot r_{3}^{2}

A_{1} \approx 313.845, A_{2} \approx 12.730, A_{3} \approx 181.077

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3 years ago
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