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Delvig [45]
3 years ago
12

A delivery truck is delivering 28 cases of paper to a store. Each case has 50 packs of paper. In each pack of paper there are 20

0 sheets,
Which expression represents the total number of sheets of paper on the truck?
O A. (28 x 50) + 200
O B. (28 +50) x 200
OC. 28 + 50 + 200
OD. 28 x 50 x 200
Mathematics
1 answer:
olga2289 [7]3 years ago
7 0

Answer:

a

Step-by-step explanation:

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S = ut + 12 at?<br> u= 10<br> a = -2<br> t =<br> Work out the value of s.
Stella [2.4K]
S = (10 x1 /2) + (1/2x- 2x 1/2²)
5 + (-0.25)
= 4.75
7 0
3 years ago
PIck from smallest to largest Smallest 8.008 8.018 8.088 8.88 8.808 Largest
frutty [35]

Answer:

<em>8.880,8.808,8.018,8.008</em>

4 0
3 years ago
7 more than the quantity 3 times 2
Zolol [24]

Answer:

13

Step-by-step explanation:

(3 times 2)+7=x

6+7=x

x=13

5 0
3 years ago
PLEASE HELP I WILL MARK YOU AS BRAINLEST
denpristay [2]

Answer:

(i) Five number summary: Minimum value = 1, Q_1=18,Median=18.5, Q_3=20.5, Maximum value = 26.

(ii) IQR = 2.5, upper fence = 24.25 and lower fence = 14.25.

(iii) 26 is an outlier of the data.

Step-by-step explanation:

The given data set is

19, 18, 23, 18, 18, 26, 19, 16, 20, 18, 17, 21

Arrange the data set in ascending order.

16, 17, 18, 18, 18, 18, 19, 19, 20, 21, 23, 26

Divide the data set in 4 equal parts.

(16, 17, 18), (18, 18, 18), (19, 19, 20), (21, 23, 26)

Minimum value = 16

Q_1=\frac{18+18}{2}=18

Median=Q_2=\frac{18+19}{2}=18.5

Q_3=\frac{20+21}{2}=20.5

Maximum value = 26

The inter quartile range (IQR) of the data is

IQR=Q_3-Q_1=20.5-18=2.5

Upper fence :

Q_3+1.5(IQR)=20.5+1.5(2.5)=24.25

Lower fence :

Q_1-1.5(IQR)=18-1.5(2.5)=14.25

If the any element of the data set lies out side the upper fence and lower fence, then it is called an outlier.

26 ∉ [14.25, 24.25]

Therefore, 26 is an outlier of the data.

4 0
3 years ago
Read 2 more answers
What is the difference 7/78 - 3 1/4=
ZanzabumX [31]
     <span> here
7 7/8
= [ (8*7) + 7 ] / 8
= (56 + 7) / 8
=63 / 8

similarly,
3 1/4
=[ (4*3) + 1] / 4
= (12 + 1) / 4
= 13/4

----------------------------
now put the values
7 7/8 - 3 1/4
= 63/8 - 13/4
here, take LCM of 8 & 4 which is 8.
now,
[ (1*63) - (2 * 13) ] / 8
= (63 - 26) / 8
= 37/8
= 4 5/8........................[ here, divide 37 by 8 which gives reminder as 5 and divisible value as 4 ]</span>
3 0
3 years ago
Read 2 more answers
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