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Dmitry_Shevchenko [17]
3 years ago
5

in the class of 10 students the probability of them passing sst206 is 1/3. then find the probability of a student passing​

SAT
1 answer:
Natali [406]3 years ago
8 0
If you have a 1/3 (33.3%) of the the class passes, that means 2/3 (66.6%) of the class will not pass. This means for every 3 students, only 1 will pass. They have a 11.1% chance of passing!
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The probability that she gets <em>more than 3 heads</em> is 0.3456.

There are only two possible outcomes for a fliped coin, either it is head, or it is tail. Since the result is independent of each other coins, the binomial distribution will be used.

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Using the binomial distribution formula:

P(X =x)=nC_x p^x (1-p)^{n-x}\\P(X =3) = 5C_3 \ (0.6)^3 (1-0.6)^{5-3}\\P(X =3) = 5C_3 \ (0.6)^3 (0.4)^{2}\\P(X=3)=0.3456

Hence the probability that she gets <em>more than 3 heads</em> is 0.3456.

Learn more on binomial distribution here: brainly.com/question/20559010

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