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MrMuchimi
3 years ago
13

Use the quadratic formula to solve the equation 4x^2-x+3=0

Mathematics
1 answer:
Vaselesa [24]3 years ago
5 0
X = -(-1) +/- sqrt((-1)^2 - 4*4*3)
      ------------------------------------   =   1/8 +/- sqrt47i 
                  2 * 4

None of the choices are correct
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Ummm there’s no right triangular
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Michael is paid $9 per hour to work at the movie theater and $7 per hour when he helps his aunt at her bakery. Michael cannot wo
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The first one/$9 an hour job.

Step-by-step explanation:

For every 32 hours he works at the $9 per hour job he makes $288.

On the other hand, for every 32 hours he works at the $7 per hour job he only makes $224.

So the only one that'll work where he gets at least $251 is the $9 an hour job.

<u>Hope this helps and have a nice day!</u>

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2 years ago
Giá trị x thoả mãn x(x − 3) + x − 3 =0 là
svet-max [94.6K]

Here we will use the trial and error method.

  • We will try putting different values of x.
<h3 /><h3>1st of all</h3><h3>x=1</h3>

\begin{gathered}\\ \sf\longmapsto 1(1-3)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto (-2)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2-2=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -4≠0\end{gathered}

<h2>Now,</h2><h3>x=2</h3>

\begin{gathered}\\ \sf\longmapsto 2(2-3)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 2(-1)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -3≠0\end{gathered}

<h2>Again,</h2><h3>x=3</h3>

\begin{gathered}\\ \sf\longmapsto 3(3-3)+3-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3(3-3)=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3×0=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 0=0\end{gathered}

<h3>☣Hence, The value of X as 3 satisfies the equation!</h3>
5 0
2 years ago
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