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Marrrta [24]
4 years ago
11

This is the last one! so please help. The question is in the picture down below !

Mathematics
2 answers:
IRISSAK [1]4 years ago
3 0

Answer:

Step-by-step explanation:

krek1111 [17]4 years ago
3 0

Answer - Part A:

I would say "whole".

Step-by-step explanation:

So, it talks about the discount being 30% or $24 dollars. This is only part of the original price.

Where, the original price is the total price. So, the means that it is the whole price.

<em>Just to help:</em>

Answer - Part B: The original cost of the jeans are $80.

Step-by-step explanation:

If you find 30% of 80, then you will have to do x/80 = 30/100. Next, you will cross multiply (x times 100 and 80 times 30), which gives you 100x and 2,400. Now, you will divide both numbers by 100. You should now have x and 24. So, x = 24.

<em>So, see? 30% of </em><em>80</em><em> is $24.</em>

<em>(This can also be used to show your work)</em>

<em />

Hope this helps! :)

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The Edward James Toy Company uses a Kanban system to make plastic wheels that are a component of several toys. The waiting time
pickupchik [31]

Answer:

N_c \approx 5.0

Step-by-step explanation:

From the question we are told that:

Waiting time for a container of the wheels during production T_w=0.25day

Average processing time is T_a=0.15 day per container

Wheel per container N_w=200

Total wheel per day D=2000

Policy variable of X=5%  

Generally the equation for Total number of container N_c is mathematically given by

N_c=DT(\frac{1+X}{N_w} )

Where

Total time T=T_w+T_a

T=0.15+0.25

Therefore

N_c=DT(\frac{1+X}{N_w} )

N_c=2000*0.40(\frac{1+0.5}{200} )

N_c=(\frac{840}{200} )

N_c=4.2

N_c \approx 5.0

Therefore the number of Kanban containers needed for the wheels is

N_c \approx 5.0

3 0
3 years ago
In the 01 July 2016, Samsung Ltd acquired the machine A by $1,502,000. Estimated useful life is 10 years, estimated residual val
Alja [10]

a) Samsung Ltd will record these Journal Entries from July 2016 to June 30, 2021, using the straight-line and revaluation methods of depreciation:

July 1, 2016 Debit Equipment $1,502,000

Credit Cash $1,502,000

  • To record the purchase of the machine A.

June 30, 2017 Debit Depreciation Expense $150,000

Credit Accumulated Depreciation $150,000

  • To record the depreciation expense for the first year.

June 30, 2018 Debit Depreciation Expense $150,000

Credit Accumulated Depreciation $150,000

  • To record the depreciation expense for the second year.

June 30, 2019 Debit Accumulated Depreciation $300,000

Credit Revaluation Reserve $300,000

  • To close the accumulated depreciation to Revaluation Reserve.

June 30, 2019 Debit Revaluation Reserve $198,000

Credit Revaluation Surplus $198,000

  • To record the Revaluation Surplus.

June 30, 2020 Debit Revaluation Expense $400,000

Credit Revaluation Reserve $400,000

  • To record the revaluation loss.

June 30, 2021 Debit Revaluation Reserve $500,000

Credit Revaluation Surplus $500,000

  • To record the revaluation surplus.

Data and Calculations:

Cost of machine on July 1, 2016 = $1,502,000

Estimated Residual Value = $2,000

Depreciable amount = $1,500,000

Estimated useful life = 10 years

Based on the straight-line method the depreciation expense for each year = $150,000 ($1,500,000/10).

Value of Machine at:

June 30, 2019 - $1,400,000

June 30, 2020 = $1,000,000

June 30, 2021 = $1,500,000

Learn more: brainly.com/question/19908089

6 0
3 years ago
If (3, y) lies on the graph of y = -(2^x), then y =<br> -8<br> 1/8<br> -6
OverLord2011 [107]
Y = -(2^3) = -8 (substitute x=3)
4 0
3 years ago
Caleb's mother said they will drive 1 /4 hour to get there, and they will drive another 1 /4 hour back. Once they arrive, Caleb'
Nezavi [6.7K]

Answer: They are away for 2\dfrac{3}{4}\ hours from home.

Step-by-step explanation:

Since we have given that

Time to get there = \dfrac{1}{4}

Time to get back = \dfrac{1}{4}

Number of soccer games = 3

Time for each soccer games = \dfrac{3}{4}

So, total time for 3 games would be

3\times \dfrac{3}{4}=\dfrac{9}{4}

So, the time for which they will be away from home is given by

\dfrac{1}{4}+\dfrac{9}{4}+\dfrac{1}4}=\dfrac{1+9+1}{4}=\dfrac{11}{4}=2\dfrac{3}{4}\ hours

Hence, they are away for 2\dfrac{3}{4}\ hours from home.

3 0
4 years ago
What is the equation of the line that passes through (4, -1) and (-2, 3)?
Rina8888 [55]
Y=mx+b

m=slope, b=y-intercept 

m=(y2-y1)/(x2-x1), b=value of y when x=0

m=(3--1)/(-2-4)

m=4/-6

m=-2/3, now we have:

y=-2x/3+b, we can solve for b using any point, I'll use (4,-1)

-1=-2(4)/3+b

-1=-8/3+b

-3/3+8/3=b

5/3=b so

y=-2x/3+5/3
3 0
3 years ago
Read 2 more answers
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