Answer:
first, you need to get y on one side. So, because the x is negative it becomes positive when you switch it to the other side. 3y= 9x+5. You then need to divide all parts by 3. 3/3= 1 so thats just y. 9/3 is 3 so thats 3x. then 5/3 is a fraction that you can write as just 5/3 or 1 and 2/3. That would leave you with y= 3x + 5/3. Then x (3) is your slope. and what you add to it (5/3) is your y int.
Answer:
y= (-1/2)x+(5/2)
Step-by-step explanation:
equation point slope
(y-y1)=m(x-x1)
y-3 = -1/2(x+1) add -3 to both sides and distribute
y=( -x/2) +(-1/2)+3 rewrite 3 as 6/2
y=(-1/2)x +(-1+6/2) solve
y= (-1/2)x+(5/2)
Answer:
21.759
Step-by-step explanation:
Given that :
Mean (m) = 25
Standard deviation (s) = 12.5
Sample size (n) = 40
α = 90%
The confidence interval is obtained using the relation:
Mean ± Zcritical * s/sqrt(n)
Zcritical at 90% confidence interval = 1.64
25 ± 1.64 * (12.5/sqrt(40))
Lower boundary : 25 - 1.64(1.9764235) = 21.75866546
Upper boundary : 25 + 1.64(1.9764235) = 28.24133454
(21.759, 28.241)
Hence, lower bound of confidence interval is : 21.759
Let
The origin of coordinates the tree
r1 = vector position of the child 1.
r2 = vector position of the child 2
Child 1:
r1 = (12i + 12j)
Child 2:
r2 = (-18i + 11j)
The scalar product will be given by:
r1.r2 = ((12) * (- 18)) + ((12) * (11)) = - 84
The scalar product of their net displacements from the tree is -84m ^ 2
