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lina2011 [118]
3 years ago
14

The pattern 96, 92, 88, 84, ________ follows the "subtract 4" rule. Study the pattern to find traits that are not obvious in the

rule. Explain.
Mathematics
1 answer:
irina1246 [14]3 years ago
4 0

Answer:

even numbers

Step-by-step explanation:

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A rectangular school banner has a length of 40 inches and a width of 24 inches. A sign is made that is similar to the school ban
e-lub [12.9K]

Answer:

The answer is 960

Step-by-step explanation:all you would have to do is multiply the lenth times width. 40x24=960  


4 0
3 years ago
Pleas someone help me with this it's my last question
ruslelena [56]

Answer:

we need to find out if the following get x = 2 as a final product

-2(x-4) = 4

-2x + 8 = 4

-2x = -4

x = 2

so it is a solution

26/x = 13

26 = 13x

x = 26/13

x = 2

so it’s a solution

-3.8x = -7.4

x = 7.4/3.8 ≠ 2

you get ≈ 1.95

so it’s not a solution

4(x-1) - 3(x-2) = -8

4x - 4 - 3x + 6 = -8

x + 2 = -8

x = -10

so it’s not a solution

5 0
3 years ago
Read 2 more answers
HELP PLEASE! 15 PTS
defon
The answer is 7/10 because the even values are 2,4,6, and the others are 7,8,9,10. Added together, it adds up to 7/10
4 0
4 years ago
Read 2 more answers
Find the smallest relation containing the relation {(1, 2), (1, 4), (3, 3), (4, 1)} that is:
professor190 [17]

Answer:

Remember, if B is a set, R is a relation in B and a is related with b (aRb or (a,b))

1. R is reflexive if for each element a∈B, aRa.

2. R is symmetric if satisfies that if aRb then bRa.

3. R is transitive if satisfies that if aRb and bRc then aRc.

Then, our set B is \{1,2,3,4\}.

a) We need to find a relation R reflexive and transitive that contain the relation R1=\{(1, 2), (1, 4), (3, 3), (4, 1)\}

Then, we need:

1. That 1R1, 2R2, 3R3, 4R4 to the relation be reflexive and,

2. Observe that

  • 1R4 and 4R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 4R1 and 1R2, then 4 must be related with 2.

Therefore \{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(4,1),(4,2)\} is the smallest relation containing the relation R1.

b) We need a new relation symmetric and transitive, then

  • since 1R2, then 2 must be related with 1.
  • since 1R4, 4 must be related with 1.

and the analysis for be transitive is the same that we did in a).

Observe that

  • 1R2 and 2R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 2R1 and 1R4, then 2 must be related with 4.
  • 4R1 and 1R2, then 4 must be related with 2.
  • 2R4 and 4R2, then 2 must be related with itself

Therefore, the smallest relation containing R1 that is symmetric and transitive is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

c) We need a new relation reflexive, symmetric and transitive containing R1.

For be reflexive

  • 1 must be related with 1,
  • 2 must be related with 2,
  • 3 must be related with 3,
  • 4 must be related with 4

For be symmetric

  • since 1R2, 2 must be related with 1,
  • since 1R4, 4 must be related with 1.

For be transitive

  • Since 4R1 and 1R2, 4 must be related with 2,
  • since 2R1 and 1R4, 2 must be related with 4.

Then, the smallest relation reflexive, symmetric and transitive containing R1 is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

5 0
3 years ago
the width of the morros in shannon's bathroom is 4/9 its length. The area of the mirror is 576 square inches. What are the dimen
fredd [130]
W=4L/9

A=LW, using W found above gives us

A=L(4L/9)

A=4L^2/9  and we were told that A=576 so

4L^2/9=576  multiply both sides by 9

4L^2=5184  divide both sides by 4

L^2=1296 take the square root of both sides

L=36, and we know that W=4L/9 so

W=4(36/9)=16

So the dimensions are: width=16in and length=36in
5 0
4 years ago
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