Answer:
T= 4p-18-pr
Step-by-step explanation:
Answer:
5/6
Step-by-step explanation:
Answer:
0.2389
Step-by-step explanation:
The amount of warpage in a type of wafer used in the manufacture of integrated circuits has mean 1.3 mm and standard deviation 0.1 mm.
A random sample of 200 wafers is drawn
we are supposed to find What is the probability that the sample mean warpage exceeds 1.305 mm
We will use central limit theorem
According to central limit theorem:
Now we are supposed to find What is the probability that the sample mean warpage exceeds 1.305 mm i.e.P(x>1.305)
Refer the z table
P(z<0.71)=0.7611
Hence the probability that the sample mean warpage exceeds 1.305 mm is 0.2389
42.39 inches squared, or the first option
A can is shaped like a cylinder. So, to find the lateral area of the tin can we must follow the lateral area formula for a cylinder, or 2 • π • radius • height
You can simply substitute the values from here.
The question wants you to use 3.14 instead of π, so the formula becomes 2 • 3.14 • radius • height
The can's radius is 1.5 inches and its height is 4.5 inches, so the formula becomes 2 • 3.14 • 1.5 • 4.5
Now we just solve: 2 • 3.14 • 1.5 • 4.5 = 42.39, so the lateral area is 42.39 inches squared.
To determine if the line is parallel, perpendicular, or neither to the given line, we must compare their slopes.
Given equation: y = -2x + 3
slope = -2
The equation of the line can be calculated by -a/b of the standard equation.
(1) y = 2x - 1 , slope = 2
Since, this is just the negative of the given line, the lines are neither parallel nor perpendicular.
(2) y = -2x + 5, slope = -2
Since the slope is equal to that of the given equation, this line is parallel with the given equation.
(3) y = 12x + 7 , slope = 12
Since the slope do not have a special relation to the slope of the given line, it is neither parallel nor perpendicular to the given.