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4 years ago

How to find area and perimeters

1 answer:

4 0

Perimeter is where you add all the side lengths together.
Area is the amount of space in an object, so you could do lxw or maybe sometimes bh/2 Or $\pi r^{2}$

You might be interested in

How can I solve no.1 and no.2?

puteri [66]

A) (-3,-4)
b) -3
c) (0,-4)
d) mini = (-4,infinity)
e) (-1,0) and (-5,0)

6 0

4 years ago

a chef makes 1 and 1/2 gallon of soup in a large pot how many one cup servings can the chef get from his large pot of soup

iragen [17]

1 gallon is 16 cups, so that means that half a gallon is 8 cups. Therefore, from 1 and 1/2 gallons of soup you can get 24 1 cup servings.

8 0

3 years ago

Read 2 more answers

Could someone pls explain me

Fiesta28 [93]

Hi! im in 7th and learning this, its 26x9 and then minus that by 9x9

5 0

3 years ago

2 Here are two equations:

MatroZZZ [7]

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Step-by-step explanation:

a. Decide whether each neither of the equations,

i (3,4)

ii. (4,2.5)

ill. (5,5)

iv. (3,2)

To decide whether each point is solution to equations or not we will put the point in the equations

Equations are:

Equation 1: 6x + 4y = 34

Equation 2: 5x – 2y = 15

i (3,4)

Putting in Equation 1:

$6(3) + 4(4) = 34\\18+16=34\\34=34\\$

Putting in Equation 2:

$5(3) - 2(4) = 15\\15-8 = 15\\7\neq 15$

ii. (4,2.5)

Putting in Equation 1:

$6(4) + 4(2.5) = 34\\24+10=34\\34=34\\$

Putting in Equation 2:

$5(4) - 2(2.5) = 15\\20-5 = 15\\15=15$

ill. (5,5)

$6(5) + 4(5) = 34\\30+20=34\\50\neq 34$

Putting in Equation 2:

$5(5) - 2(5) = 15\\25-10 = 15\\15=15$

iv. (3,2)

$6(3) + 4(2) = 34\\18+8=34\\26\neq 34$

Putting in Equation 2:

$5(3) - 2(2) = 15\\15-4 = 15\\11\neq 15$

Hence,

(3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. Is it possible to have more than one (x, y) pair that is a solution to both

equations?

The simultaneous linear equations' solution is the point on which the lines intersect. Two lines can intersect only on one point. So a linear system cannot have more than one point as a solution

So,

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Keywords: Linear equations, Ordered pairs

Learn more about linear equations at:

#LearnwithBrainly

8 0

3 years ago

Kellie currently has an average of 75 in her English class. If her grade is the mean of all her assignments, what would a grade

andriy [413]

Answer:

I just summited it, it was "Her mean grade would go up".

Step-by-step explanation:

8 0

3 years ago