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lubasha [3.4K]
3 years ago
12

Plssss 40 pointsplsssss

Mathematics
2 answers:
kolezko [41]3 years ago
7 0
Wait why does it say 11 ????????????????
levacccp [35]3 years ago
6 0

Step-by-step explanation:

The first statement is incorrect. It should be

seg AB is congr. to seg DC

Here are the reasons:

1. Given

2. Given

3. Theorem: Alt int angles of parallel lines

4. Theorem: Congruence of segments is reflexive

5. SAS

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For what point on the curve of y=8x^2 - 3x is the slope of a tangent line equal to -67
AleksandrR [38]

The point on the curve is (–4, 140)

Solution:

Given y=8x^2-3x and slope is –67.

slope = –67

$\frac{dy}{dx}=-67$  – – – – (1)

Now calculate \frac{dy}{dx} for the given curve y=8x^2-3x.

Using differential rule:

$\frac{d}{dx}(x^n)=nx^{n-1}

$\frac{dy}{dx}=\frac{d}{dx}(8x^2-3x)

    $=\frac{d}{dx}(8x^2)-\frac{d}{dx}(3x)

    $=(8\times2x^{2-1})-(3\times1x^{1-1})

    $=16x^1-3x^0

    $=16x-3

$\frac{dy}{dx}=16x-3 – – – – (2)

Equate (1) and (2).

16x-3=-67

16x=-67+3

16x=-64

⇒ x = –4

Substitute x = –4 in y.

⇒ y=8(-4)^2-3(-4)

⇒    =8(16)+12

⇒ y = 140

Hence, the point on the curve given is (–4, 140).

3 0
4 years ago
If the figure forms the base of a right solid 110 centimeters high, find the surphase area.​
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How do you draw a line through a point using the slope?
Mumz [18]
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What is the quotient [3y+2/3y] / [6y^2+4y/3y+2]
givi [52]
<span>[3y+2/3y] / [6y^2+4y/3y+2]
Steps
First, divide fractions
= (3y + 2)(3y + 2)/3y(6y^2 + 4y)
Then... factor 3y(6y^2 + 4y): 6y^2(3y + 2)
= (3y + 2)(3y + 2)/6y^2(3y + 2)
Then, cancel the common factor: 3y + 2
= 3y + 2/6y^2</span>
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4 years ago
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