If (a, b) is on the graph of a function f(x), then (b, a) is on the graph of the inverse.
We have points on the graph of a function: {(-3, 9), (-1, 1), (0, 0), (2, 4)}.
The points on the graph of the inverse: {(9, -3), (1, -1), (0, 0), (4, 2)}.
<h3>Answer: (4, 2), (0, 0), (1, -1).</h3>
The restrictions for the equation is that the denominator can not be zero. So the restrictions for x would be what values make the denominator zero.
7x^2 + 6x = 0
factor
x(7x + 6) = 0
multiply any number by 0 and you get 0. So either x = 0 or 7x+6 = 0
since there's a x in the numerator x/x = 1 so this will not be a restriction. Then the only restriction is:
7x+6 = 0
7x = -6
x = -6/7
Answer:
Step-by-step explanation:
We are to find the equation a line that passes through the point (8, 1) and which is perpendicular to a line whose equation is
.
We know that the slope of line which is perpendicular to another line is the negative reciprocal of the slope of the other line so it will be
.
Then, we will find the y-intercept of the line using the standard equation of a line:
Therefore, the equation of the line will be
.
Answer:
The answer is 17.8
Step-by-step explanation: