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melisa1 [442]
3 years ago
5

100 POINTS BRAINLIEST QUESTION ATTACHED.

Mathematics
2 answers:
borishaifa [10]3 years ago
7 0

Answer:

Step-by-step explanation:

3√6-10√2√3

=3√6-10√(2*3)

=3√6-10√6

=-7√6

The answer is A.

Dimas [21]3 years ago
3 0

ANSWER

- 7 \sqrt{6}

EXPLANATION

The given radical expression is

3 \sqrt{6}  - 10 \sqrt{2}  \times  \sqrt{3}

Recall and use

\sqrt{a}  \times  \sqrt{b}  =  \sqrt{ab}

to obtain;

3 \sqrt{6}  -10 \sqrt{2 \times 3}

Simplify the second radicand.

3 \sqrt{6}  - 10 \sqrt{6}

We have two like surds so we can simplify to obtain;

- 7 \sqrt{6}

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2x(5x-2) expanding brackets
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Step-by-step explanation:

2x(5x-2)

= 2x*5x - 2x*2 (Distributive property)

= 10x^2 - 4x

8 0
3 years ago
What is the greatest common factor of the number pair 18 and 24
True [87]

Answer:

Greatest common factor (GCF) of 18 and 24 is 6.

3 0
3 years ago
4. Determine all unknown sides and angles to 1 decimal place.
Ksju [112]

Answer:

The unknown sides are 60.81cm and 51.57cm while the unknown angle is 58degrees

Step-by-step explanation:

4a) Given the following

Opposite side = 38cm (side facing the given angle)

Required

Adjacent and hypotenuse side

According to SOH CAH TOA

tan \theta = \frac{opp}{hyp}\\tan 32=\frac{38}{hyp}\\hyp=\frac{38}{tan 32}\\hyp=\frac{38}{0.6249}\\hyp=  60.81cm

Next is to get the adjacent

Cos 32=\frac{adj}{60.81}\\adj=60.81cos32\\adj=60.81(0.8480)\\adj= 51.57cm

Next is to get the missing

Since sum of angle in the triangle is 180degrees

32 + 90 + x = 180

122 + x = 180

x = 180 - 122

x = 58degrees

7 0
3 years ago
Twenty five heat lamps are connected in a greenhouse so, that when one lamp fails, another takes over immediately (only one lamp
olga55 [171]

Answer:

P = 0.006

Step-by-step explanation:

Given

n = 25 Lamps

each with mean lifetime of 50 hours and standard deviation (SD) of 4 hours

Find probability that the lamp will be burning at end of 1300 hours period.

As we are not given that exact lamp, it means we have to find the probability where any of the lamp burning at the end of 1300 hours, So we have

Suppose i represents lamps

P (∑i from 1 to 25 (X_i > 1300)) = 1300

= P(X^{'}> \frac{1300}{25})                  where X^{'} represents mean time of a single lamp

= P (Z> \frac{52-50}{\frac{1}{\sqrt{25}}})                Z is the standard normal distribution which can be found by using the formula

Z = Mean Time (X^{'}) - Life time of each Lamp (50 hours)/ (SD/\sqrt{n})

Z = (52-50)/(4/\sqrt{25}) = 2.5

Now, P(Z>2.5) = 0.006 using the standard normal distribution table

Probability that a lamp will be burning at the end of 1300 hours period is 0.006

4 0
4 years ago
the metro theater has 20 rows of seats with 18 seats I each row. Ticket cost $5. the theater's income in dollars if all seat are
Mumz [18]
500 IS THE ANSWER XD

7 0
3 years ago
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