The line containing the vector <em>q</em> can be obtained by scaling <em>q</em> by an arbitrary scalar <em>t</em>. To make this line pass through the point <em>p</em>, translate this line by a vector <em>p</em> pointing from the origin to <em>p</em>.
So the line we want has equation
<em>r</em>(<em>t</em>) = <em>q</em><em>t</em> + <em>p</em> = (14, -8)<em>t</em> + (-4, 12) = (14<em>t</em> - 4, 12-8<em>t</em>)
where <em>t</em> is any real number.
Answer:
what?
Step-by-step explanation:
Answer:
Step-by-step explanation:
Here, to compute the expected value you only need to multiply each payout value by the correspondently probability and add all the results. More exactly,
Expected value= 1*0.35+2*0.2+5*0.1+8*0.2+10*0.15=4.35
Answer:
The probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is 0.65173.
Step-by-step explanation:
We are given that a company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 259.2 cm and a standard deviation of 2.1 cm. For shipment, 17 steel rods are bundled together.
Let = <u><em>the average length of rods in a randomly selected bundle of steel rods</em></u>
The z-score probability distribution for the sample mean is given by;
Z = ~ N(0,1)
where, = population mean length of rods = 259.2 cm
= standard deviaton = 2.1 cm
n = sample of steel rods = 17
Now, the probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is given by = P( > 259 cm)
P( > 259 cm) = P( > ) = P(Z > -0.39) = P(Z < 0.39)
= <u>0.65173</u>
The above probability is calculated by looking at the value of x = 0.39 in the z table which has an area of 0.65173.