A certain television is advertised as a 55-inch TV (the diagonal length). If the width of the TV is 42 inches, how many inches t
all is the TV? Round your answer to the nearest tenth.
1 answer:
Answer:
69.20in
Step-by-step explanation:
Given data
diagonal of the TV d= 55in
Widht of the TV w= 42 in
Hight h= ???
Applying the Pythagoras theorem
d^2= w^2+ h^2
substitute
55^2= 42^2+ h^2
3025= 1764+ h^2
3025+1764= h^2
4789= h^2
h=√4789
h= 69.20
Hence the Heigth is 69.20in
You might be interested in
So the total number of students equals 8+17 = 25 students
Proportionally:
Thus,
boys out of the 100 students.
It is false because it is equal to 2 the line is straight down
2. 24-7p=10
-7p=-14
p=2
3. x+(x+1)+(x+2)=72
3x+3=72
3x=69
x=23
4. x+(x+2)+(x+4)=48
3x+6=48
3x=42
x=14
7. 40-2x=8
-2x=-32
x=16
8. 1/2x+4=12
1/2x=8
x=16
Answer:
D. 172.5 inches cubed
Step-by-step explanation:
Have a good day :)
(4,2) is is the distance from these coordinates
