A certain television is advertised as a 55-inch TV (the diagonal length). If the width of the TV is 42 inches, how many inches t
all is the TV? Round your answer to the nearest tenth.
1 answer:
Answer:
69.20in
Step-by-step explanation:
Given data
diagonal of the TV d= 55in
Widht of the TV w= 42 in
Hight h= ???
Applying the Pythagoras theorem
d^2= w^2+ h^2
substitute
55^2= 42^2+ h^2
3025= 1764+ h^2
3025+1764= h^2
4789= h^2
h=√4789
h= 69.20
Hence the Heigth is 69.20in
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