Answer:
( a + b)³ = (a + b)( a² + 2ab + b²)
= a³ + 2a²b + ab² + a²b + 2ab² + b³
<h2>= a³ + 3a²b + 3ab² + b³</h2>
Hope this helps you
Answer: 20 hours
Step-by-step explanation:
Since, One watch is slow and loses two minutes every hour
⇒ 1 hour of slow watch = 62 minutes
And, the other one is fast and gains one minute every hour.
⇒ 1 hour of fast watch = 59 minutes,
Hence, in 1 hour, the difference between slow and fast watch in 1 hour = 62 - 59 = 3 minutes.
⇒ The between slow and fast watch in 20 hours = 20 × 3 = 60 minutes or 1 hour.
Hence, after 20 hours the difference between the watches will be 1 hours.
Answer:
![=36\sqrt{7}i](https://tex.z-dn.net/?f=%3D36%5Csqrt%7B7%7Di)
Step-by-step explanation:
sqrt of 7-11=2i
simplify to ![6\cdot \:2\sqrt{9}\sqrt{7}i](https://tex.z-dn.net/?f=6%5Ccdot%20%5C%3A2%5Csqrt%7B9%7D%5Csqrt%7B7%7Di)
then sqrt of 9=3
then we simplify again to ![=36\sqrt{7}i](https://tex.z-dn.net/?f=%3D36%5Csqrt%7B7%7Di)
hope this helps and if you don't mind please consider giving me brainliest