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3 years ago

How many classifications shown contain organisms whose cells do not have nuclei?

Mathematics

2 answers:

loris [4]3 years ago

8 0

The answer is letter D

Maslowich3 years ago

7 0

The answer to this is letter D

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Which point is the image of point R(4, -7) first reflected across the x-axis and then across the y-axis?

nasty-shy [4]

Answer:

(-4, 7)

Step-by-step explanation:

It would be the exact opposite of point R because it was rotated about 180 degrees from it's original location

6 0

2 years ago

I need help on this, please hurry and thank you!

inna [77]

Answer:

$A.\ a_n=n^2+1$

Step-by-step explanation:

$Check:$

$a_n=n^2+1\\\\a_1=1^2+1=1+1=2\qquad CORRECT\\\\a_2=2^2+1=4+1=5\qquad CORRECT\\\\a_3=3^2+1=9+1=10\qquad CORRECT\\\\a_4=4^2+1=16+1=17\qquad CORRECT\\\\a_5=5^2+1=25+1=26\qquad CORRECT$

Used PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

First Power, next Addition

4 0

3 years ago

Read 2 more answers

Calculating the degrees of freedom, the sample variance, and the estimated standard error for evaluations using the t statistic

Yuliya22 [10]

Answer:

a) For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

$df = n-1= 10-1=9$

d.9

b) $s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15$

a.15

c) For this case we have the sample size n = 25 and the sample variance is $s^2 =400$ , the standard error can founded with this formula:

$SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80$

Step-by-step explanation:

Part a

For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

$df = n-1= 10-1=9$

d.9

Part b

From a sample we know that n=41 and SS= 600, where SS represent the sum of quares given by:

$SS = \sum_{i=1}^n (X_i -\bar X)^2$

And the sample variance for this case can be calculated from this formula:

$s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15$

a.15

Part c

For this case we have the sample size n = 25 and the sample variance is $s^2 =400$ , the standard error can founded with this formula:

$SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80$

8 0

3 years ago

Write a verbal phrase for the following algebraic expression 12y

aleksandrvk [35]

The product of a number y and 12 or 12 times a number y. These are both equivalent expressions to 12y

6 0

3 years ago

Please be correct !!!!!!!!!!!!!!!!!xx

givi [52]

<span>$2,022.92 would be the answer

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5 0

3 years ago

Read 2 more answers