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3 years ago

Use the change of base formula to evaluate the logarithms to the nearest thousandth.

Mathematics

2 answers:

klasskru [66]3 years ago

8 0

Answer:

log3(6) = 1.631

log5(20) = 1.861

log2(1/5) = -2.322

Step-by-step explanation:

Free_Kalibri [48]3 years ago

5 0

Answer:

log36 = 1.631

log520 = 1.861

log2 (1/5) = –2.322

Step-by-step explanation:

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Find the value of the discriminant for all the equations. 1.5q2 +2q–3=0 2.3u2 -4u+1=0 3.7s2 +9s–4=0 4.6w2 –8w+5=0 5.5p2 +7p–3=0

kicyunya [14]

Answer:

Case 1: a = 1.5, b = 2, c = -3

$D = 22$

Case 2: a = 2.3, b = -4, c = 1

$D = 6.8$

Case 3: a = 3.7, b = 9, c = -4

$D = 140.2$

Case 4: a = 4.6, b = -8, c = 5

$D = -28$

Case 5: a = 5.5, b = 7, c = -3

$D = 115$

Case 6: a = 6.9, b = -5, c = 2

$D = -30.2$

Case 7: a = 7.2, b = 6, c = -4

$D = 151.2$

Case 8: a = 8.3, b = -3, c = 4

$D = -123.8$

Case 9: a = 9.9, b = 4, c = -7

$D = 293.2$

Case 10: a = 10.4, b = 8, c = -5

$D = 272$

Step-by-step explanation:

For all second order polynomial, the discriminant is equal to:

$D = b^{2}-4\cdot a \cdot c$

Case 1: a = 1.5, b = 2, c = -3

$D = 22$

Case 2: a = 2.3, b = -4, c = 1

$D = 6.8$

Case 3: a = 3.7, b = 9, c = -4

$D = 140.2$

Case 4: a = 4.6, b = -8, c = 5

$D = -28$

Case 5: a = 5.5, b = 7, c = -3

$D = 115$

Case 6: a = 6.9, b = -5, c = 2

$D = -30.2$

Case 7: a = 7.2, b = 6, c = -4

$D = 151.2$

Case 8: a = 8.3, b = -3, c = 4

$D = -123.8$

Case 9: a = 9.9, b = 4, c = -7

$D = 293.2$

Case 10: a = 10.4, b = 8, c = -5

$D = 272$

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