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zhenek [66]
3 years ago
6

Rewrite the equation below so that it does not have fractions. 3+3/4x=2/5

Mathematics
1 answer:
slavikrds [6]3 years ago
4 0

in order to get rid of the denominator, multiply it with all the other numbers

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What is the value of y?<br> Circle the correct answer.<br> 43 - y = 17<br> y = 29<br> y = 26
nekit [7.7K]
Y=26 because 43-26=17 and 17=17
6 0
3 years ago
Read 2 more answers
Please help confused with half life /compound interest problems
jekas [21]
Half life means only half of matter is left, which means half is decayed/radiated. 
Formula for half life is
t/2 = [(elapsed time)*(log2)]/[log(beginning amount/ending amount)]
1. t/2 = [(10)*(log2)]/[log(100/76.1)] = 25.378 minutes.
 t/2 = [10 * 0.301]/[log 1.314] = [3.01]/[0.1186] = 25.378
2. 53.12 = [(T)*(log2)]/[log(15/4)], on solving we get, T = 101.29 days
 53.12 = [T * 0.301]/[log 3.75] = [0.301 * T]/[0.574],
 T = [53.12 * 0.574]/[0.301] = [30.49]/[0.301] = 101.29<span />
6 0
3 years ago
On the planet of Mercury, 4-year-olds average 3 hours a day unsupervised. Most of the unsupervised children live in rural areas,
erastova [34]

Answer:

a

The distribution of  X is normal

b

P(X  <  1.4) = 0.12654

c

P(X  >  3.5) = 0.36051

Step-by-step explanation:

From the question we are told that

   The population mean is  \mu =  3 \  hours

   The standard deviation is  \sigma  =  1.4 \ hours

Generally given from the question that the amount of time spent alone by the population size is normally distributed then then the distribution of X (i.e the amount of time spent by the sample size (the one Mercurian)) will be normally distributed

  Generally the probability that the child spend less than one hour in a day is mathematically represented as

        P(X  <  1.4) =  P(\frac{X - \mu}{\sigma} < \frac{1.4 - \mu}{\sigma}   )

Here \frac{X - \mu}{\sigma }  =  Z (The\ standardized\ value\ of\  X)

So

      P(X  <  1.4) =  P(Z < \frac{1.4 - 3.0}{1.4}   )

     P(X  <  1.4) =  P(Z < -1.1429  )

From the z-table the value of  

        P(Z < -1.1429  )=0.12654

So     P(X  <  1.4) = 0.12654

Generally the percentage of children that spends over 3.5 hours unsupervised is mathematically represented as

        P(X  >  3.5) =  P(\frac{X - \mu}{\sigma} > \frac{3.5 - \mu}{\sigma}   )

        P(X >  3.5) =  P(Z > \frac{3.5 - 3.0}{1.4}   )

        P(X >  3.5) =  P(Z > 0.3571  )

From the z-table the value of  

        P(Z >0.3571  )=0.36051

So     P(X  >  3.5) = 0.36051

5 0
3 years ago
Choose a rule for the translation.​
pantera1 [17]
Your answer would be B, X+2 Y-1
3 0
3 years ago
(-2 √(-49)(5 √(-100)
Tamiku [17]

Answer:

The answer is... 700

4 0
3 years ago
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