Answer: $2,561.50
(I = A - P = $211.50)
Equation:
A = P(1 + rt)
Calculation:
First, converting R percent to r a decimal
r = R/100 = 18%/100 = 0.18 per year.
Solving our equation:
A = 2350(1 + (0.18 × 0.5)) = 2561.5
A = $2,561.50
The total amount accrued, principal plus interest, from simple interest on a principal of $2,350.00 at a rate of 18% per year for 0.5 years is $2,561.50.
Answer:
a. A frame is a list of individuals in the population being studied.
Step-by-step explanation:
We are asked to choose the correct definition of frame from our given choices.
We know that a frame, in statistics, is a list of all those within a population who can be sampled. It may include individuals, households or institutions.
We also know that a frame is the source material or device from which a sample is drawn.
Upon looking at our given choices, we can see that option 'a' is the correct choice.
Since the limit becomes the undetermined form

it means that both polynomials have a root at
. So, we can fact both numerator and denominator:


So, the fraction becomes

Now, as x approaches 1, you have no problems anymore:

<h3>
<u>Explanation</u></h3>

- Calculate the slope with two given coordinate by using rise over run.

These two coordinate points are part of the graph and can be used to find the slope.

Substitute the coordinate points in the formula.

Therefore, the slope is 2.
Rewrite the equation in slope-intercept.

- Calculate the y-intercept by substituting any given points in new rewritten equation.

I will be substituting these coordinate points in the equation.

Substitute x = 0 and y = 5 in the equation.

Therefore the y-intercept is (0,2).
Rewrite the equation.

<h3>
<u>Answer</u></h3>
<u>
</u>
<em>If</em><em> </em><em>you</em><em> </em><em>have</em><em> </em><em>any</em><em> </em><em>questions</em><em> </em><em>related</em><em> </em><em>to </em><em>the</em><em> </em><em>answer</em><em>,</em><em> </em><em>feel</em><em> </em><em>free to</em><em> </em><em>ask me</em><em> </em><em>via</em><em> </em><em>comment</em><em>.</em><em> </em>