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Paladinen [302]

2 years ago

12

Paano nakaapekto ang ugali ni tuan putli sa relasyon nilang dalawa ni manik buangsi Anong Ebidensiya mula sa binasa ang magpapat

unay dito?

1 answer:

Pavel [41]2 years ago

3 0

I don’t know what that says but free points for meeeee

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A sample of pure lithium nitrate contains 7. 99% lithium by mass. What is the % lithium by mass in a sample of pure lithium nitr

Shalnov [3]

Considering the definition of percentage by mass, the sample of pure lithium nitrate contains 7.99% lithium by mass.

<h3>Definition of percentage by mass</h3>

The percentage by mass expresses the concentration and indicates the amount of mass of solute present in 100 grams of solution.

In other words, the percentage by mass of a component of the solution is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.

The percentage by mass is calculated as the mass of the solute divided by the mass of the solution, the result of which is multiplied by 100 to give a percentage. This is:

$percentage by mass=\frac{mass of solute}{mass of solution}x100$

<h3>This case</h3>

Because percent by mass indicates the ratio of solute to solution based on mass, if the sample has twice the mass of the first sample, the ratio remains constant.

So the percentage by mass is the same.

That is, the sample of pure lithium nitrate contains 7.99% lithium by mass.

.

Learn more about percent by mass:

brainly.com/question/18646836?referrer=searchResults

3 0

2 years ago

A sample of a compound that contains only the elements c, h, and n is completely burned in o2 to produce 44. 0 g of co2, 45. 0 g

Elan Coil [88]

Answer:

B. CH₅N

Explanation:

The combustion reaction of a compound CₐHₓNₙ with O₂ is:

CₐHₓNₙ + O₂ → a CO₂ + X/2 H₂O + n NO₂

Where 1 mole of CₐHₓNₙ with an excess of O₂ produce a moles of CO₂, X/2 moles of H₂O and n moles of NO₂

Thus, you need to convert the mass of CO₂ and H₂O to moles to find the C:H ratio and determine a possible empirical formula thus:

Moles CO₂ (Molar mass 44g/mol):

44g ₓ (1mol / 44g) = 1 mole CO₂ = 1 mole C

Mole of H₂O (Molar mass 18g/mol):

45g ₓ (1 mol / 18g) = 2.5 moles H₂O = 5 moles H

Thus, in the compound you have 5 moles of H per mole of C, and a possible empirical formula is:

B. CH₅N

The only structure that meet this C:H ratio

8 0

2 years ago