Answer:
Step-by-step explanation:
I think you mean a^2 + 16a + 64.
The x-intercepts are the values of a for which the polynomial equals zero.
a^2 + 16a + 64 = (a+8)^2 = 0
a = 8
The x-intercept is 8.
The area of the garden enclosed by the fencing is
A(x, y) = xy
and is constrained by its perimeter,
P = x + 2y = 200
Solve for x in the constraint equation:
x = 200 - 2y
Substitute this into the area function to get a function of one variable:
A(200 - 2y, y) = A(y) = 200y - 2y²
Differentiate A with respect to y :
dA/dy = 200 - 4y
Find the critical points of A :
200 - 4y = 0 ⇒ 4y = 200 ⇒ y = 50
Compute the second derivative of A:
d²A/dy² = -4 < 0
Since the second derivative is always negative, the critical point is a local maximum.
If y = 50, then x = 200 - 2•50 = 100. So the farmer can maximize the garden area by building a (100 ft) × (50 ft) fence.
Answer:

Step-by-step explanation:

So the eqn becomes

AND this equal to

Hence the variable x has 0 as its coefficient.
8n is 8 x n. If n is 2, then 8n is 8 x 2 which is 16! Hope that helps!
Somewhere you're given the equation for height as a function of time:
... h(t) = -16t² + v₀·t . . . . . . where v₀ is the initial vertical velocity in ft/s
For v₀ = 224, this becomes
... h(t) = -16t² + 224t
And this can be rewritten in vertex form as
... h(t) = -16(t² + 14t)
... h(t) = -16(t² + 14t +7²) +16·7² . . . . . complete the square (add the square of half the t coefficient inside parentheses; add the opposite of that amount outside parentheses)
... h(t) = -16(t +7)² + 784
The vertex of this downward-opening parabola is (7, 784), so ...
The rocket reaches its maximum height at 7 seconds.
The maximum height of the rocket is 784 feet.