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prohojiy [21]
3 years ago
10

Please help me on this will give you brainliest

Mathematics
1 answer:
Lelu [443]3 years ago
3 0

Answer:

5/6>7/9

Step-by-step explanation:

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Please help!<br> Find the quadratic function with the roots of -2 and P
Marrrta [24]

The roots routine will return a column vector containing the roots of a polynomial. The general syntax is


  z = roots(p)


where p is a vector containing the coefficients of the polynomial ordered in descending powers.

Given a vector



which describes a polynomial




we construct the companion matrix (which has a characteristic polynomial matching the polynomial described by p), and then find the eigenvalues of it (which are the roots of its characteristic polynomial)



Example


Here is an example of finding the roots to the polynomial



--> roots([1 -6 -72 -27])



ans =  

  12.1229  

  -5.7345  

  -0.3884

3 0
3 years ago
Can you help me answer this question?<br> Increase £184 by 3%
miskamm [114]

Answer:

189.52

Step-by-step explanation:

184 x 0.03

5.52

184 + 5.52

189.52

6 0
3 years ago
Read 2 more answers
Is 30/100 equivalent to 3/1000?
andre [41]
No it is not equivalent
6 0
4 years ago
What type of answer will 2.25 + .75 have? Explain.
julia-pushkina [17]

Answer:

the answer will have a decimal but there is no such thing as type of answer.

there are many ways to answer this

5 0
3 years ago
Read 2 more answers
A yoga studio sells monthly memberships. The function f(x) = −x2 + 50x − 264 models the profit in dollars, where x is the number
-BARSIC- [3]
<h2>Answer:</h2>

<em>x = 6, x = 44; The zeros represent the number of monthly memberships where no profit is made.</em>

<h2>Explanation:</h2>

Here we have the function:

f(x) = -x^2 + 50x - 264

that models the profit in dollars, where x is the number of memberships sold. In order to get the zeros we'll use the quadratic formula:

\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a} \\ \\ \\ For: \\ \\ a=-1,\:b=50,\:c=-264:\quad x_{1,\:2}=\frac{-50\pm \sqrt{50^2-4\left(-1\right)\left(-264\right)}}{2\left(-1\right)} \\ \\ \\ x_{1}=\frac{-50+\sqrt{50^2-4\left(-1\right)\left(-264\right)}}{2\left(-1\right)}=\frac{-50+\sqrt{50^2-4\cdot \:1\cdot \:264}}{-2\cdot \:1}=\frac{-50+\sqrt{1444}}{-2\cdot \:1}=6 \\ \\ \\

x_{2}=\frac{-50-\sqrt{50^2-4\left(-1\right)\left(-264\right)}}{2\left(-1\right)}=\frac{-50-\sqrt{50^2-4\cdot \:1\cdot \:264}}{-2\cdot \:1}=\frac{-50-\sqrt{1444}}{-2}=44

So the zeros are:

x=6 \\ \\ x=44

The zeros occurs when f(x)=0, so we can conclude that at those points there is no any profit.

In conclusion:

<em>x = 6, x = 44; The zeros represent the number of monthly memberships where no profit is made.</em>

7 0
4 years ago
Read 2 more answers
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