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densk [106]
3 years ago
13

Find the distance between each pair of points in the coordinate plane.

Mathematics
1 answer:
labwork [276]3 years ago
8 0

Answer:

1) 3 units

2)4 units

3) 5 units

4)10 units

Step-by-step explanation:

We can use the Distance Formula to find the distance between the two points given to us. The Distance Formula is for points (x1 , y1) & (x2 , y2) is

★ Distance = √[ (x2 - x1)² + (y2 - y1)²]

<u>1) (0,0) & (0,3)</u>

⇒ Distance = √ [ (3-0)²+(0-0)² ]

⇒ Distance = √ [ 3² ]

⇒ Distance = 3 units .

====================================

<u>2</u><u>) (0,0) & (</u><u>4</u><u>,</u><u>0</u><u>)</u>

⇒ Distance = √ [ (4-0)²+(0-0)² ]

⇒ Distance = √ [ 4² ]

⇒ Distance = 4 units .

====================================

<u>3) (0,0) & (4,3)</u>

⇒ Distance = √ [ (3-0)²+(4-0)² ]

⇒ Distance = √ [ 3²+ 4² ]

⇒ Distance = √ 9 + 16

⇒ Distance = √25

⇒ Distance = 5 units .

====================================

<u>4</u><u>) (0,0) & (</u><u>8</u><u>,</u><u>6</u><u>)</u>

⇒ Distance = √ [ (8-0)²+(6-0)² ]

⇒ Distance = √ [ 8²+ 6² ]

⇒ Distance = √ 64 + 36

⇒ Distance = √100

⇒ Distance = 10 units .

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Which value of a and b make the equation true?<br> (2xy)4
EastWind [94]

An equation is formed of two equal expressions. The correct option is B.

<h3>What is an equation?</h3>

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

The complete option is:

Which values of a and b make the equation true?

\dfrac{(2xy)^4}{4xy}=4x^ay^b

A)a = 0, b = 0

B)a = 3, b = 3

C)a = 4, b = 4

D)a = 5, b = 5

The given equation can be simplified as shown below,

\dfrac{(2xy)^4}{4xy}=4x^ay^b\\\\\dfrac{2^4 \times x^4 \times y^4}{4xy}=4x^ay^b\\\\\dfrac{16x^4y^4}{4xy} = 4x^ay^b\\\\4x^{(4-1)}y^{(4-1)} = 4x^ay^b\\\\4x^3y^3 = 4x^ay^b

Now, comparing the two sides of the equation, the value of a and b should 3 for the equation to be satisfied.

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Learn more about Equation:

brainly.com/question/2263981

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