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8_murik_8 [283]
2 years ago
5

Find the surface area of the prism 12in 4 in 3in 5in 5in 6in​

Mathematics
1 answer:
Mamont248 [21]2 years ago
5 0

Answer:

Area of trapezoid:

12 + 6<-- your two bases of the trapezoid = 18

18 x 4 = 72, 72 divided by 2 = 36

now we multiply by 2 since there are 2 trapezoids:

36 x 2 = 72

Area of rectangle in front:

6 x 3 = 18

Area of the 2 rectangles on the sides:

5 x 3 = 15

(multiply by 2 since there are two rectangles on both sides)

15 x 2 = 30

Area of rectangle on the back:

12 x 3 = 36

Now lets add up all the areas:

72 + 18 + 30 + 36 = 156 in2 is your answer.

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The volume of the box as a polynomial in the variable x is x(12 - 2x)(7 - 2x)

<h3>How to determine the volume?</h3>

The complete question is added as an attachment

From the attached image, we have:

Length = 12 - 2x

Width = 7 - 2x

Height = x

The volume is calculated as:

Volume = Length * Width * Height

Substitute the known values in the above equation

Volume = (12 - 2x) * (7 - 2x) * x

This gives

Volume = x(12 - 2x)(7 - 2x)

Hence, the volume of the box as a polynomial in the variable x is x(12 - 2x)(7 - 2x)

Read more about polynomial at:

brainly.com/question/4142886

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A newspaper prints that the average square footage of a house in Cleveland is significantly less than 2,379 square feet.
tatyana61 [14]

Answer: i’m confused on what the question is

Step-by-step explanation:

6 0
3 years ago
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In the opening scene of the movie Raiders of the Lost Ark, Indiana Jones replaces a golden statue with a bag of sand. The platfo
chubhunter [2.5K]

Answer:

1920π

Step-by-step explanation:

First, you need to find the volume of the statue in terms of pi.

Volume of cylinder formula:

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Then, you need to find the mass of the statue.

Mass:

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Now, you need to find the volume. Since the sand has to weigh the same as the statue, the mass is going to stay the same. To find the volume you need to do:

V=mass of sand/density

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1920π

Note: I had to do the exact same problem on Khan Academy. This is right.

3 0
2 years ago
What is f(g(x)) for x &gt; 5?
mel-nik [20]

Answer:

\large\boxed{B.\ 4x^2-41x+105}

Step-by-step explanation:

f(x)=4x-\sqrt{x}\\\\g(x)=(x-5)^2\\\\f(g(x))\to\text{put}\ x=(x-5)^2\ \text{to}\ f(x):\\\\f(g(x))=f\bigg((x-5)^2\bigg)=4(x-5)^2-\sqrt{(x-5)^2}\\\\\text{use}\\(a-b)^2=a^2-2ab+b^2\\\sqrt{x^2}=|x|\\\\f(g(x)=4(x^2-2(x)(5)+5^2)-|x-5|\\\\x>5,\ \text{therefore}\ x-5>0\to|x-5|=x-5\\\\f(g(x))=4(x^2-10x+25)-(x-5)\\\\\text{use the distributive property:}\ a(b+c)=ab+ac\\\\f(g(x))=(4)(x^2)+(4)(-10x)+(4)(25)-x-(-5)\\\\f(g(x))=4x^2-40x+100-x+5\\\\\text{combine like terms}\\\\f(g(x))=4x^2+(-40x-x)+(100+5)\\\\f(g(x))=4x^2-41x+105

6 0
3 years ago
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