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Shtirlitz [24]
3 years ago
13

A bank is advertising the following savings account.

Mathematics
1 answer:
Vlad1618 [11]3 years ago
8 0

Answer:

6.66%

Step-by-step explanation:

((1 + r/m)^n) - 1

Interest rate , r = 6.5%

m = number of compounding times per period = 4 (quarterly interest)

((1 + 0.065/4)^4) - 1

((1 + 0.01625) ^4) - 1

((1.01625)^4) - 1

1.06660 - 1

= 0.0666

0.0666 * 100%

= 6.66%

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Please help<br><br><br> AOB = ?<br><br> BOC = ?<br><br> BOD = ?
goldfiish [28.3K]
From the diagram, we know that it is an angle that adds up to 360

So

x+4x+2x+10+5x+50=360


Gather like terms

12x+60=360

Move sixty to the other side as a negative number

12x=300

Divide both sirs by twelve

x is equal to 25

AOB is 2x+10

Sub x in 2*25+10

AOB is 60

BOC is 5x+50

5*25+50, which is 175

BOD is x+2x+10

Which is 3x+10

Sub x

3*25+10 which is 85

:)
7 0
3 years ago
Read 2 more answers
Shannon test-drives a car in Germany and drives 95 kilometers per hour. What is her speed in the miles per hour ?
Reptile [31]

Answer:

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Step-by-step explanation:

8 0
3 years ago
Solve the following equation. Remember to check for extraneous solutions 1/(x-6) + (x/(x-2)) = (4/(x²-8x+12)).
xxMikexx [17]

Answer:

-1, 2, 6

Step-by-step explanation:

We have to solve the equation as follows: 1/(x-6) + (x/(x-2)) = (4/(x²-8x+12)).

Now, we have, \frac{1}{x-6} +\frac{x}{x-2} = \frac{4}{x^{2}-8x+12 }

⇒\frac{(x-2)+x(x-6)}{(x-2)(x-6)} = \frac{4}{x^{2}-8x+12 }

⇒\frac{x-2+x^{2}-6x }{(x-2)(x-6)} =\frac{4}{(x-2)(x-6)}

⇒\frac{(x-2)(x-6)}{x^{2}-5x-2 }=\frac{(x-2)(x-6)}{4}

⇒(x-2)(x-6)[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0

⇒ (x-2)(x-6) =0 or, [\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0

If, (x-2)(x-6) =0, then x=2 or x=6

If, [\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0, then x^{2} -5x-2=4

and (x-6)(x+1) =0

Therefore, x=6 or -1

So the solutions for x are -1, 2 6. (Answer)

4 0
3 years ago
What is the difference of the polynomials?
Olenka [21]
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8 0
3 years ago
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A point is a ______.
Ksju [112]
A point is a geometry figure named with lowercase letters (I'm pretty sure)
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