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3 years ago

A bank is advertising the following savings account.

Mathematics

1 answer:

Vlad1618 [11]3 years ago

8 0

Answer:

6.66%

Step-by-step explanation:

((1 + r/m)^n) - 1

Interest rate , r = 6.5%

m = number of compounding times per period = 4 (quarterly interest)

((1 + 0.065/4)^4) - 1

((1 + 0.01625) ^4) - 1

((1.01625)^4) - 1

1.06660 - 1

= 0.0666

0.0666 * 100%

= 6.66%

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4.13

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To find out how many kilometres they ran in all you have to do 1.43+2.7 =4.13

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3 years ago

Read 2 more answers

Cerell’s Clothing

liq [111]

Answer:

One. first what you want to do you want to convert 20% into a decimal and a way to do that you need to move a decimal two times to the left. when finding the percent of something you will always move the decimal two times to left

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Sorry if this doesn't help, have a great day/night, hope it helps, and stay safe!

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3 years ago

Select the equivalent expression

slava [35]

Answer: c
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3 years ago

A video game was originally priced at $60.

pantera1 [17]

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3 years ago

What should I buy? A study conducted by a research group in a recent year reported that of cell phone owners used their phones i

Llana [10]

Answer:

The probability that seven or more of them used their phones for guidance on purchasing decisions is 0.7886.

Step-by-step explanation:

The question is incomplete:

What should I buy? A study conducted by a research group in a recent year reported that 57% of cell phone owners used their phones inside a store for guidance on purchasing decisions. A sample of 14 cell phone owners is studied. Round the answers to at least four decimal places. What is the probability that seven or more of them used their phones for guidance on purchasing decisions?

We can model this as a binomial random variable, with p=0.57 and n=14.

$P(x=k)=\dbinom{n}{k} p^{k}q^{n-k}$

a) We have to calculate the probability that seven or more of them used their phones for guidance on purchasing decisions:

$P(x\geq7)=\sum_{k=7}^{14}P(x=k)\\\\\\$

$P(x=7)=\dbinom{14}{7} p^{7}q^{7}=3432*0.0195*0.0027=0.1824\\\\\\P(x=8) = \dbinom{14}{8} p^{8}q^{6}=3003*0.0111*0.0063=0.2115\\\\\\P(x=9) = \dbinom{14}{9} p^{9}q^{5}=2002*0.0064*0.0147=0.1869\\\\\\P(x=10) = \dbinom{14}{10} p^{10}q^{4}=1001*0.0036*0.0342=0.1239\\\\\\P(x=11) = \dbinom{14}{11} p^{11}q^{3}=364*0.0021*0.0795=0.0597\\\\\\P(x=12) = \dbinom{14}{12} p^{12}q^{2}=91*0.0012*0.1849=0.0198\\\\\\P(x=13) = \dbinom{14}{13} p^{13}q^{1}=14*0.0007*0.43=0.004\\\\\\$

$P(x=14) = \dbinom{14}{14} p^{14}q^{0}=1*0.0004*1=0.0004\\\\\\$

$P(x\geq7)=0.1824+0.2115+0.1869+0.1239+0.0597+0.0198+0.004+0.0004\\\\P(x\geq7)=0.7886$

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3 years ago