The answer is -12 hope this helps
Answer:
<u><em>Answer is below</em></u>
Step-by-step explanation:
<em><u> Factor left side of equation.</u></em>
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<em><u>Set factors equal to 0.</u></em>

I'm pretty sure it is A, graphing calculators might .help with these
The value of the constant a will the system of linear equations 6x-5y=3 and 3x+ay=1 have no solution is -5/2
<h3>System of equation</h3>
For a system of equation to have no solution, the expression on both sides must be different.
Given the system of equation
6x-5y=3 and
3x+ay=1
For the equations to have no solution, the a1/a2= b1/b2
Substitute
6/3 = -5/a
Cross multiply
2 = -5/a
a= -5/2
Hence the value of the constant a will the system of linear equations 6x-5y=3 and 3x+ay=1 have no solution is -5/2
Learn more on system of equation here: brainly.com/question/14323743
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Step-by-step explanation:
The general form of the quadratic equation is :

The given equation is x²+4x+20=0
On comparing the given equation and the general equation, we find that
a = 1, b = 4 and c = 20
Hence, the correct option is a=1 b =4 c = 20.
If the equation is 2x²+6x+5=0, then
a = 2, b = 6 and c = 5
If the equation is -2x²+x+5
a = -2, b = 1 and c = 5