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3 years ago

A cyclist travels 7 km from home to the park.

Mathematics

1 answer:

adell [148]3 years ago

4 0

Answer:

28 km per hour

Step-by-step explanation:

First determine the amount of time that the trip took

17:55 - 17:40 = :15 or 15 minutes

We need the time in hours

15 minutes * 1 hour/ 60 minutes = 15/60 hours = 1/4 hours

To determine speed, take distance and divide by time

7 km ÷( 1/4 hours)

Copy dot flip

7 * 4/1

28 km per hour

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300 students in a high school freshman class are surveyed about what kinds of pets they have. Of the 300 students, 200 have a do

katrin2010 [14]

This Question is not complete

Complete Question:

300 students in a high school freshman class are surveyed about what kinds of pets they have. Of the 300 students, 200 have a dog, 180 have a cat, and 150 have a cat and a dog. Using this information, answer each of the following questions, Let D be the event that a randomly selected student has a dog and C be the event that a randomly selected student has a cat.

a . What is P(D), the probability that a student in the class has a dog?

b. What is P(C), the probability that a student in the class has a cat?

c. What is P(D and C), the probability that a student in the class has a dog and a cat?

d. What is P(D or C), the probability that a student in the class has a dog or a cat?

Answer:

a. 2/3

b) 3/5

c) 1/2

d) 19/ 15 = 1 4/15

Step-by-step explanation:

The formula for probability =

Number of possible outcomes ÷ Number of events.

Total number of Students = 300

Number of Students that have a dog = 200

Number of Students that have a cat = 180

Number of Students that have a dog and cat = 150

a. What is P(D), the probability that a student in the class has a dog?

In the question, the given data is interpreted as :

Number of possible outcomes = 200

Number of events = 300

P(D) = 200/300

= 2/3

Therefore, the probability that a student has a dog = 2/3

b. What is P(C), the probability that a student in the class has a cat?

In the question, the given data is interpreted as :

Number of possible outcomes = 180

Number of events = 300

P(D) = 180/300

= 3/5

Therefore, the probability that a student has a cat = 3/5

c. What is P(D and C), the probability that a student in the class has a dog and a cat?

In the question, the given data is interpreted as :

Number of possible outcomes = 150

Number of events = 300

P(D) = 150/300

= 1/2

Therefore, the probability that a student has a dog and cat = 1/2

d. What is P(D or C), the probability that a student in the class has a dog or a cat?

The is calculated as

P(D) + P(C)

In the above question,

P(D) is calculated as 2/3

P(C) is calculated as 3/5

Therfore, P(D or C), the probability that a student in the class has a dog or a cat is calculated as:

= 2/3 +3/5

= 19/15 = 1 4/15

7 0

3 years ago

In a grouped frequency distribution one interval is listed as 50-54. Assuming that the scores are measuring a continuous variabl

aliina [53]

Answer:

a. 49.5 and 54.5

Step-by-step explanation:

Class interval is a range of a value that is used to group data into equal size for easy analysis and representation of the data. It is applicable in the divisions of a histogram or bar chart into classes. Examples of class interval are 50-54, 55-59, 60-64, 65-69, 70-74 etc.

Class limit is the minimum and maximum value the class interval may contain. The minimum value is called the lower class limit and the maximum value is called the upper class limit. For class interval 50-54, the lower class limit is 50 and the upper class limit is 54.

Class boundaries are the numbers used to separate classes. It is the real limits of a class. For non-overlapping classes, the lower class boundary of each class is calculated by subtracting 0.5 from the lower class limit. The upper class boundary of each class is calculated by adding 0.5 to the upper class limit. Example: For class interval 50-54, the lower class boundary is 49.5 and the upper class class boundary is 54.5

Considering the question given, to get the real limits of the interval 50-54, 0.5 is subtracted from the lower class limit to give 49.5. Also, 0.5 is added to the upper class limit to give 54.5.

4 0

4 years ago

The table shows some values of a function of the form y

kherson [118]

The value of c, the constant of the function y = ax² + bx + c, exists -3.

<h3>What is an equation?</h3>

An equation exists as an expression that indicates the relationship between two or more numbers and variables.

Given that: y = ax² + bx + c

At point (4, 21)

21 = a(4²) + 4b + c .......(1)

At point (5, 32)

32 = a(5²) + 5b + c .........(2)

At points (6, 45)

45 = a(6²) + 6b + c .......(3)

Therefore, the value of a = 1, b = 2 and c = -3.

The value of c, the constant of the function y = ax² + bx + c, exists -3.

To learn more about equations refer to:

brainly.com/question/2972832

#SPJ9

4 0

1 year ago

after an oil pipeline burst one morning gas prices went up by $2.20 per gallon at the afternoon you bought 10 gallons of gas for

mr Goodwill [35]

53.90/10=5.39
5.39-2.20=3.19
3.19 dollars per gallon

6 0

3 years ago

Read 2 more answers

Add or subtract write the ansewr in simplest form 1/4+1/10

astra-53 [7]

Answer:

7/20

Step-by-step explanation:

7 0

3 years ago