For one dice 1/6
for the other dice 1/6
it equals 2 /6
which is simplified to 1/3
Step-by-step explanation:
A ball is launched straight up in the air from a height of 6 feet. The velocity as a function of time t is given by :
f(t) = -32 t+285
Height of the ball is :

C is constant. Here the ball is launched from a height of 6 feet. So,

At t = 2 s, 
At t = 9 s, 
Between 2 s and 9 s, the ball's height changed is : 1275 - 512 = 763 m.
Answer:
426 cm^2
Step-by-step explanation:
Let, the area of the given figure be A
Let's imagine that the rectangle (at the bottom right) is present.
Then, A = Area of trapezium - Area of rectangle
= { 1/2 * ( 18 + (20+4) ) * ( 13+9 ) } - ( 4 * 9 )
= 462 - 36
= 426
[If there's any mistake, please inform me]