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3 years ago

The inequality is what

Mathematics

1 answer:

VARVARA [1.3K]3 years ago

7 0

Answer:

(−=|>)=∑(−=,=|>)=∑(−=|=,>)(=|>)=∑(−=|>)(=|>)

Step-by-step explanation:

Substitutex=cos\alp,\alp∈[0:;π]

\displaystyle Then\; |x+\sqrt{1-x^2}|=\sqrt{2}(2x^2-1)\Leftright |cos\alp +sin\alp |=\sqrt{2}(2cos^2\alp -1)Then∣x+

1−x

∣=

(2x

−1)\Leftright∣cos\alp+sin\alp∣=

(2cos

\alp−1)

\displaystyle |\N {\sqrt{2}}cos(\alp-\frac{\pi}{4})|=\N {\sqrt{2}}cos(2\alp )\Right \alp\in[0\: ;\: \frac{\pi}{4}]\cup [\frac{3\pi}{4}\: ;\: \pi]∣N

cos(\alp−

)∣=N

cos(2\alp)\Right\alp∈[0;

]∪[

3π

;π]

1) \displaystyle \alp \in [0\: ;\: \frac{\pi}{4}]\alp∈[0;

]

\displaystyle cos(\alp -\frac{\pi}{4})=cos(2\alp )\dotscos(\alp−

)=cos(2\alp)…

2. \displaystyle \alp\in [\frac{3\pi}{4}\: ;\: \pi]\alp∈[

3π

;π]

\displaystyle -cos(\alp -\frac{\pi}{4})=cos(2\alp )\dots−cos(\alp−

)=cos(2\alp)…

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An employee suspected of having used an illegal drug is given two tests that operate independently of each other. Test A has pro

puteri [66]

Answer:

0.02 or 2%

Step-by-step explanation:

The probability that test A is negative if the illegal drug has been used (P(A|N)) is 0.1 while the probability that test B is negative if the illegal drug has been used (P(B|N)) is 0.2.

Therefore, the probability that neither test is positive if the illegal drug has been used is:

$P(A \cap B|N) = P(A|N)* P(B|N) = 0.1 *0.2\\P(A \cap B|N) = 0.02$

There is a 0.02 or 2% probability that neither test is positive if the illegal drug has been used.

7 0

4 years ago

Read 2 more answers

Need help on these, thank you!

tensa zangetsu [6.8K]

Answer:

$5x+2 , 2x^2+5x-2,\frac{x^2+5x}{2-x^2}$

Step-by-step explanation:

We are given f(x) and g(x)

1. (f+g)(x)

(f+g)(x) = f(x) + g(x)

= $x^2+5x+2-x^2$

= $5x+2$

Domain : All real numbers as it there exists a value of (f+g)(x) f every x .

2. (f-g)(x)

(f-g)(x) = f(x)-g(x)

= $x^2+5x-2+x^2$

= $2x^2+5x-2$

Domain : All real numbers as it there exists a value of (f-g)(x) f every x .

Part 3 .

$(\frac{f}{g})(x)\\(\frac{f}{g})(x) = \frac{f(x)}{g(x)}\\=\frac{x^2+5x}{2-x^2}$

Domain : In this case we see that the function is not defined for values of x for which the denominator becomes 0 or less than zero . Hence only those values of x are defined for which

$2-x^2>0$