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REY [17]
3 years ago
15

Given the following perfect square trinomial, fill in the missing term 4x2 + ___x + 49

Mathematics
2 answers:
Arisa [49]3 years ago
6 0

Answer:

wheres the square trinomail

Step-by-step explanation:

marissa [1.9K]3 years ago
6 0

Answer:

Below.

Step-by-step explanation:

Taking the square roots of the 2 given terms we write it as a binomial

(2x + 7(2x + 7)

This = 4x^2 +  14x + 14x + 49

= 4x^2 + 28x + 49

So the missing number is 28.

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Solution would be where the two lines intersect but they never do. They are parallel and never meet

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A rock is dropped from the top of a building and hits the ground at a velocity of
soldier1979 [14.2K]

The height of the building comes to be 81 feet.

Initial velocity u= 0 feet/sec

Final velocity v= 72 feet/sec

The acceleration due to gravity g =32ft /sec²

Height of the building h= suppose h

<h3>What is the equation of motion?</h3>

The equation of a motion is:

v^{2} =u^{2} +2gh

Where u and v are the initial and final velocities.

72^{2} =0+2*32*h\\144 = 64h\\h=81

So, the height of the building = 81 feet.

Therefore, the height of the building comes to be 81 feet.

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2 years ago
Read 2 more answers
Between 0 degrees Celsius and 30 degrees Celsius, the volume V (in cubic centimeters) of 1 kg of water at a temperature T is giv
Ira Lisetskai [31]

Answer:

T = 3.967 C

Step-by-step explanation:

Density = mass / volume

Use the mass = 1kg and volume as the equation given V, we will come up with the following equation

D = 1 / 999.87−0.06426T+0.0085043T^2−0.0000679T^3

   = (999.87−0.06426T+0.0085043T^2−0.0000679T^3)^-1

Find the first derivative of D with respect to temperature T

dD/dT = \dfrac{70000000\left(291T^2-24298T+91800\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^2}

Let dD/dT = 0 to find the critical value we will get

\dfrac{70000000\left(291T^2-24298T+91800\right)}  = 0

Using formula of quadratic, we get the roots:

T =  79.53 and T = 3.967

Since the temperature is only between 0 and 30, pick T = 3.967

Find 2nd derivative to check whether the equation will have maximum value:

-\dfrac{140000000\left(395178T^4-65993368T^3+3286558821T^2+2886200857800T-121415215620000\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^3}

Substituting the value with T=3.967,

d2D/dT2 = -1.54 x 10^(-8)    a negative value. Hence It is a maximum value

Substitute T =3.967 into equation V, we get V = 0.001 i.e. the volume when the the density is the highest is at 0.001 m3 with density of

D = 1/0.001 = 1000 kg/m3

Therefore T = 3.967 C

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3 years ago
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