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Vedmedyk [2.9K]
3 years ago
12

What is the solution to l + (-3)=9

Mathematics
1 answer:
wariber [46]3 years ago
7 0

Answer:

12

Step-by-step explanation:

I + (-3) = 9

Lets isolate I:

9 - (-3) = I

       12 = I

Check:

12 + (-3) = 9

          9 = 9

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H(x)=-2x-5, find h(-2)
Vedmedyk [2.9K]

Answer:

h(-2) = -1

Step-by-step explanation:

h(x)=-2x-5

Let x= -2

h(-2)=-2*-2-5

      = 4 -5

h(-2) = -1

5 0
3 years ago
Help please!! someone explain
valina [46]
Well, the answer is 12. This is because you need to add the inverse operation. So for (6x-6)  You add 6 or  the second number( the one that doesn't have the x in front of it)because it is the opposite/inverse operation.You basically just add 6 and because the opposite of subtraction is addition. You then cross is out because it will equal zero. Then with the 6x, you add 6 as well because what you do to one side, you must do the same to the other. so 6+6=12. SO x=12.
                +
8 0
3 years ago
Saul works at the local car dealership. He makes 2% commission on all sales. He sells a car worth $20,000. What is his commissio
Gala2k [10]
<span>Saul works at the local car dealership.
=> He makes 2% commission on all sales.
=> He sells a car worth $20,000.
Question: What is his commission
=> We need to get the 2% value of 20 000 dollars for his commission. To do that simply convert 2% into decimal value then multiply it with 20 000 dollars.
=> 2% / 100% = 0.02
=> 20 000 * .02 = 400 dollars is his commission.</span>



3 0
3 years ago
Read 2 more answers
I don't know if this is right... please someone help mee
worty [1.4K]
For the first circle, let's use the pythagorean theorem

\bf \textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;c=\sqrt{8^2+15^2}\implies c=\sqrt{289}\implies c=17

now, it just so happen that the hypotenuse on that triangle, is actually 17, but we used the pythagorean theorem to find it, and the pythagorean theorem only works for right-triangles.

 so if the hypotenuse is actually 17, that means that triangle there is actually a right-triangle, meaning that the radius there, and the outside line there, are both meeting at a right-angle.

when an outside line touches the radius line, and they form a right-angle, the outside line is indeed a tangent line, since the point of tangency is always a right-angle with the radius.



now, let's check for second circle

\bf \textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;c=\sqrt{11^2+14^2}\implies c=\sqrt{317}\implies c\approx 17.8044938

well, low and behold, we didn't get our hypotenuse as 16 after all, meaning, that triangle is NOT a right-triangle, and that outside line is not touching the radius at a right-angle, therefore is NOT a tangent line.



let's check the third circle

\bf \textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;c=\sqrt{33^2+56^2}\implies c=\sqrt{4225}\implies c=\stackrel{33+32}{65}

this time, we did get our hypotenuse to 65, the triangle is a right-triangle, so the outside line is indeed a tangent line.
6 0
2 years ago
What is the probability of the complement of spinning an even number by us using the spinner below
KiRa [710]

Answer:

3/8

Step-by-step explanation:

there are 8 options in total

3 of them arr even

6 0
3 years ago
Read 2 more answers
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