Answer:
the company must buy 22 gallons to paint this entire area
Step-by-step explanation:
The circumference of the tank is given and is C = 2(pi)r, where r is the area.
118 ft
Here the circumference is C = 2(pi)(r) = 118 ft, which leads to r = ------------ ≈
18.79 ft ≈ r 2(pi)
The area of the sides is A = (circumference)(height), or approximately
(118 ft)(50 ft) = 5900 ft², and the area of the top is A = πr², which here comes to (π)(18.79 ft)² ≈ 1109 ft². Combining these two sub-areas, we get:
A(total) = 1109 ft² + 5900 ft² ≈ 7009 ft²
To determine how many gallons of paint will be needed to paint only the top and sides, we divide 7009 ft² by the coverage rate, which is
320 ft²
-----------
1 gallon
which results in:
7009 ft²
---------------------- ≈ 21.9 gallons
320 ft² / gallon
Since the paint comes only in full gallon cans, the company must buy 22 gallons to paint this entire area.
As we can see
![\\ \sf\longmapsto D_f=\[1,11\]](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20D_f%3D%5C%5B1%2C11%5C%5D)
So having 1 and 11 as domain we can say the equation is
As it's greater than and equal to the answer can be equal to (=) form.
26. 5x^2+3x-2
The leading coefficient is 5.
28. -5c^2-3c+4
The leading coefficient is -5.
30. t^5+2t+11t-3
The leading coefficient is 1.
Answer:
sat: 28:63
sun:32:72
Step-by-step explanation:
thats is.
